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Find the derivative of the following function.

y=ln(4x^(4))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=ln(4x4) y=\ln \left(4 x^{4}\right) \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=ln(4x4) y=\ln \left(4 x^{4}\right) \newlineAnswer: y= y^{\prime}=
  1. Apply Chain Rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.\newlineFor y=ln(4x4)y = \ln(4x^{4}), the outer function is ln(u)\ln(u) and the inner function is u=4x4u = 4x^{4}.\newlineFirst, we find the derivative of the outer function with respect to its argument uu, which is 1/u1/u.\newlineThen, we will find the derivative of the inner function with respect to xx, which is the derivative of 4x44x^{4}.
  2. Differentiate Inner Function: Differentiate the inner function 4x44x^{4} with respect to xx. Using the power rule, which states that the derivative of xnx^n with respect to xx is nx(n1)n*x^{(n-1)}, we differentiate 4x44x^{4}. The derivative of 4x44x^{4} with respect to xx is 4×4x3=16x34 \times 4x^{3} = 16x^{3}.
  3. Combine Derivatives: Combine the derivatives of the outer and inner functions using the chain rule.\newlineThe derivative of yy with respect to xx is the derivative of the outer function times the derivative of the inner function.\newlineSo, y=1u×(16x3)y' = \frac{1}{u} \times (16x^{3}), where u=4x4u = 4x^{4}.
  4. Substitute uu: Substitute uu back into the derivative.\newlineSince u=4x4u = 4x^{4}, we substitute it back into the expression for yy'.\newliney=14x4×(16x3)y' = \frac{1}{4x^{4}} \times (16x^{3}).
  5. Simplify Expression: Simplify the expression.\newlineWe can simplify the expression by canceling out common factors.\newliney=16x34x4=4x3x4y' = \frac{16x^{3}}{4x^{4}} = \frac{4x^{3}}{x^{4}}.
  6. Cancel xx Terms: Simplify the expression further by canceling xx terms.\newlineWhen dividing powers with the same base, we subtract the exponents.\newliney=4x43=4x.y' = \frac{4}{x^{4-3}} = \frac{4}{x}.

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