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Find the derivative of the following function.

y=e^(8x^(6)+5x^(5))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=e8x6+5x5 y=e^{8 x^{6}+5 x^{5}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=e8x6+5x5 y=e^{8 x^{6}+5 x^{5}} \newlineAnswer: y= y^{\prime}=
  1. Identify uu as exponent: To find the derivative of the function y=e8x6+5x5y=e^{8x^{6}+5x^{5}}, we will use the chain rule. The chain rule states that the derivative of eue^{u}, where uu is a function of xx, is eue^{u} times the derivative of uu with respect to xx.
  2. Find derivative of uu: First, let's identify uu as the exponent of ee. In this case, u=8x6+5x5u = 8x^{6} + 5x^{5}.
  3. Apply power rule: Now we need to find the derivative of uu with respect to xx, which is uu'. To do this, we apply the power rule to each term separately. The power rule states that the derivative of xnx^n is nx(n1)n*x^{(n-1)}.
  4. Apply chain rule: The derivative of the first term, 8x68x^{6}, is 48x548x^{5} because we multiply the exponent 66 by the coefficient 88 and then decrease the exponent by 11. The derivative of the second term, 5x55x^{5}, is 25x425x^{4} because we multiply the exponent 55 by the coefficient 55 and then decrease the exponent by 11. So, 48x548x^{5}00.
  5. Final derivative: Now we can apply the chain rule. The derivative of yy with respect to xx, yy', is eue^{u} times uu'. So, y=e8x6+5x5×(48x5+25x4)y' = e^{8x^{6}+5x^{5}} \times (48x^{5} + 25x^{4}).
  6. Final derivative: Now we can apply the chain rule. The derivative of yy with respect to xx, yy', is eue^{u} times uu'. So, y=e8x6+5x5×(48x5+25x4)y' = e^{8x^{6}+5x^{5}} \times (48x^{5} + 25x^{4}).We have found the derivative of the function without any mathematical errors. The final answer is y=e8x6+5x5×(48x5+25x4)y' = e^{8x^{6}+5x^{5}} \times (48x^{5} + 25x^{4}).

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