Find the derivative of the following function. y=e^(-8x^(5)) Answer: y^(')=

Identify Function and Rule: Identify the function and the rule to use for differentiation. We have the function y = e^(-8x^(5)). To find the derivative, we will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.Apply Chain Rule: Apply the chain rule to differentiate the function. The outer function is e^u, where u = -8x^(5). The derivative of e^u with respect to u is e^u. The inner function is u = -8x^(5), and its derivative with respect to x is -8 * 5x^(5-1) = -40x^(4).Multiply Derivatives: Multiply the derivatives of the outer and inner functions. The derivative of y with respect to x, denoted as y', is the product of the derivative of the outer function and the derivative of the inner function. Therefore, y' = e^(-8x^(5)) * (-40x^(4)).Simplify Expression: Simplify the expression for the derivative. y' = -40x^(4) * e^(-8x^(5)) This is the simplified form of the derivative.

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Find the derivative of the following function.

y=e^(-8x^(5))
Answer:
y^(')=

Find the derivative of the following function. $\newline$ $y=e^{-8 x^{5}}$ $\newline$ Answer: $y^{\prime}=$

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Find derivatives using logarithmic differentiation

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Q. Find the derivative of the following function.

\newline

y=e^{-8 x^{5}}

\newline

Answer:

y^{\prime}=

Identify Function and Rule: Identify the function and the rule to use for differentiation. $\newline$ We have the function $y = e^{-8x^{5}}$ . To find the derivative, we will use the chain rule, which states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
Apply Chain Rule: Apply the chain rule to differentiate the function. $\newline$ The outer function is $e^u$ , where $u = -8x^{5}$ . The derivative of $e^u$ with respect to $u$ is $e^u$ . The inner function is $u = -8x^{5}$ , and its derivative with respect to $x$ is $-8 \times 5x^{5-1} = -40x^{4}$ .
Multiply Derivatives: Multiply the derivatives of the outer and inner functions. $\newline$ The derivative of $y$ with respect to $x$ , denoted as $y'$ , is the product of the derivative of the outer function and the derivative of the inner function. Therefore, $y' = e^{(-8x^{5})} \times (-40x^{4})$ .
Simplify Expression: Simplify the expression for the derivative. $\newline$ $y' = -40x^{4} \cdot e^{-8x^{5}}$ $\newline$ This is the simplified form of the derivative.