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Find the derivative of the following function.

y=3^(x^(3))
Answer: 
y^(')=

Find the derivative of the following function.\newliney=3x3 y=3^{x^{3}} \newlineAnswer: y= y^{\prime}=

Full solution

Q. Find the derivative of the following function.\newliney=3x3 y=3^{x^{3}} \newlineAnswer: y= y^{\prime}=
  1. Identify Function: Identify the function to differentiate.\newlineWe are given the function y=3x3y = 3^{x^3}. We need to find its derivative with respect to xx, which is denoted as yy'.
  2. Apply Chain Rule: Apply the chain rule for differentiation.\newlineThe chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is 3u3^{u} (where u=x3u = x^{3}) and the inner function is u=x3u = x^{3}.
  3. Differentiate Outer Function: Differentiate the outer function with respect to the inner function.\newlineThe derivative of 3u3^u with respect to uu is 3uln(3)3^u \cdot \ln(3), where ln(3)\ln(3) is the natural logarithm of 33.
  4. Differentiate Inner Function: Differentiate the inner function with respect to xx. The derivative of u=x3u = x^3 with respect to xx is 3x23x^2.
  5. Apply Chain Rule: Apply the chain rule by multiplying the derivatives from Step 33 and Step 44.\newliney=(3uln(3))(3x2)y' = (3^u \cdot \ln(3)) \cdot (3x^2)\newlineSince u=x3u = x^3, we substitute back to get:\newliney=(3x3ln(3))(3x2)y' = (3^{x^3} \cdot \ln(3)) \cdot (3x^2)
  6. Simplify Derivative: Simplify the expression for the derivative.\newliney=3x3ln(3)3x2y' = 3^{x^3} \cdot \ln(3) \cdot 3x^2\newliney=3x2ln(3)3x3y' = 3x^2 \cdot \ln(3) \cdot 3^{x^3}

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