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Find an explicit formula for the arithmetic sequence

-45,-30,-15,0,dots
Note: the first term should be 
c(1).

c(n)=◻

Find an explicit formula for the arithmetic sequence\newline45,30,15,0, -45,-30,-15,0, \ldots \newlineNote: the first term should be c(1) c(1) .\newlinec(n)= c(n)=\square

Full solution

Q. Find an explicit formula for the arithmetic sequence\newline45,30,15,0, -45,-30,-15,0, \ldots \newlineNote: the first term should be c(1) c(1) .\newlinec(n)= c(n)=\square
  1. Identify sequence type and pattern: Identify the type of sequence and the pattern between the terms. The sequence 45,30,15,0,-45, -30, -15, 0, \ldots has a common difference between consecutive terms, indicating that it is an arithmetic sequence. The common difference can be found by subtracting any term from the subsequent term. For example, 30(45)=15-30 - (-45) = 15.
  2. Determine first term: Determine the first term of the sequence, which is given as 45-45. This term will be represented as c(1)c(1).
  3. Use explicit formula: Use the explicit formula for an arithmetic sequence, which is c(n)=c(1)+(n1)dc(n) = c(1) + (n-1)d, where c(1)c(1) is the first term and dd is the common difference. We have already identified c(1)c(1) as 45-45 and dd as 1515.
  4. Substitute values into formula: Substitute the values of c(1)c(1) and dd into the formula to find the explicit formula for the sequence. The formula becomes c(n)=45+(n1)×15c(n) = -45 + (n-1)\times15.
  5. Simplify formula: Simplify the formula by distributing the 1515 into the parentheses. This gives us c(n)=45+15n15c(n) = -45 + 15n - 15.
  6. Combine like terms: Combine like terms to get the final explicit formula for the sequence. The formula simplifies to c(n)=15n60c(n) = 15n - 60.

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