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Find an explicit formula for the arithmetic sequence

-2,-14,-26,-38,dots
Note: the first term should be 
d(1).

d(n)=

Find an explicit formula for the arithmetic sequence\newline2,14,26,38,..  -2,-14,-26,-38, \ldots \text {.. } \newlineNote: the first term should be d(1) d(1) .\newline d(n) = \(\square\)

Full solution

Q. Find an explicit formula for the arithmetic sequence\newline2,14,26,38,..  -2,-14,-26,-38, \ldots \text {.. } \newlineNote: the first term should be d(1) d(1) .\newline d(n) = \(\square\)
  1. Identify Type: Identify whether the given sequence is geometric or arithmetic. The sequence 2,14,26,38,-2, -14, -26, -38, \ldots has a common difference between consecutive terms, so it is an arithmetic sequence.
  2. Use Explicit Formula: Use the explicit formula for an arithmetic sequence, d(n)=d(1)+(n1)dd(n) = d(1) + (n-1)d, where d(1)d(1) is the first term and dd is the common difference. For the sequence 2,14,26,38,-2, -14, -26, -38, \ldots, the first term, d(1)d(1), is 2-2 and we need to find the common difference, dd.
  3. Calculate Common Difference: Calculate the common difference, dd, by subtracting the first term from the second term: d=14(2)=14+2=12d = -14 - (-2) = -14 + 2 = -12.
  4. Substitute Values: Substitute the values of d(1)d(1) and dd into the formula to write an explicit formula for the sequence. The expression for the sequence 2,14,26,38,-2, -14, -26, -38, \ldots is d(n)=2+(n1)(12)d(n) = -2 + (n-1)(-12).
  5. Simplify Expression: Simplify the expression to get the final explicit formula for the sequence. The simplified expression is d(n)=212(n1)=212n+12=12n+10d(n) = -2 - 12(n-1) = -2 - 12n + 12 = -12n + 10.

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