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Einsteinium-253 is an element that loses about 
(2)/(3) of its mass every month. A sample of Einsteinium253 has 450 grams.
Write a function that gives the sample's mass in grams, 
S(t),t months from today.

S(t)=

Einsteinium253-253 is an element that loses about 23 \frac{2}{3} of its mass every month. A sample of Einsteinium253253 has 450450 grams.\newlineWrite a function that gives the sample's mass in grams, S(t),t S(t), t months from today.\newlineS(t)= S(t)=\square

Full solution

Q. Einsteinium253-253 is an element that loses about 23 \frac{2}{3} of its mass every month. A sample of Einsteinium253253 has 450450 grams.\newlineWrite a function that gives the sample's mass in grams, S(t),t S(t), t months from today.\newlineS(t)= S(t)=\square
  1. Identify initial mass and decay rate: Step 11: Identify the initial mass and the decay rate. The initial mass of the sample is given as 450450 grams. The decay rate is 23\frac{2}{3} of its mass every month, which means that the sample retains 123=131 - \frac{2}{3} = \frac{1}{3} of its mass each month.
  2. Write exponential decay function: Step 22: Write the exponential decay function. The general form of an exponential decay function is S(t)=S0×(decay factor)tS(t) = S_0 \times (\text{decay factor})^{t}, where S0S_0 is the initial mass and the decay factor is the fraction of mass that remains after each time period. In this case, the decay factor is 13\frac{1}{3}.
  3. Substitute known values: Step 33: Substitute the known values into the decay function. The initial mass S0S_0 is 450450 grams, and the decay factor is 13\frac{1}{3}. Therefore, the function that models the mass of the sample after tt months is S(t)=450×(13)tS(t) = 450 \times \left(\frac{1}{3}\right)^t.
  4. Simplify function: Step 44: Simplify the function if necessary. In this case, the function is already in its simplest form, so no further simplification is needed.

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