Consider this matrix:[2−2amp;−8amp;7]Find the inverse of the matrix. Give exact values. Non-integers can be given as decimals or as simplified fractions.
Q. Consider this matrix:[2−2−87]Find the inverse of the matrix. Give exact values. Non-integers can be given as decimals or as simplified fractions.
Write Matrix Determinant: Write down the matrix and its determinant.The matrix is:A=[2amp;−8−2amp;7]To find the inverse of a 2×2 matrix, we need to calculate its determinant. The determinant of a 2×2 matrix A=[aamp;bcamp;d] is ad−bc.For our matrix A, the determinant (det(A)) is:det(A)=(2)(7)−(−8)(−2)det(A)=14−16det(A)=−2
Check Non-Zero Determinant: Check if the determinant is non-zero.Since the determinant is non-zero (det(A)=−2), the matrix has an inverse. If the determinant were zero, the matrix would not have an inverse.
Find Matrix of Minors: Find the matrix of minors.For a 2×2 matrix, the matrix of minors is simply a matrix where each element is replaced by the determinant of the submatrix formed by removing the row and column of that element.For our matrix A, the matrix of minors is:\left[\begin{array}{cc}\(\newline7 & -2 (\newline\)-8 & 2\end{array}\right]\)
Apply Checkerboard of Signs: Apply the checkerboard of signs to the matrix of minors to get the cofactor matrix.For a 2×2 matrix, this means we change the sign of the elements at position (1,2) and (2,1).The cofactor matrix is:\left[\begin{array}{cc}\(\newline7 & 2 (\newline\)8 & 2\end{array}\right]\)
Transpose Cofactor Matrix: Transpose the cofactor matrix.The transpose of a matrix is obtained by swapping the rows and columns.The transpose of the cofactor matrix is:[7amp;82amp;2]
Multiply by 1/det(A): Multiply the transpose of the cofactor matrix by 1/det(A). Since det(A)=−2, we multiply each element of the transposed cofactor matrix by −1/2 to get the inverse of the original matrix.The inverse matrix is:\left[\begin{array}{cc}\(\newline-7/2 & -8/2 (\newline\)-2/2 & -2/2\end{array}\right]\)
Simplify Inverse Matrix: Simplify the fractions in the inverse matrix.The simplified inverse matrix is:\left[\begin{array}{cc}\(\newline-3.5 & -4 (\newline\)-1 & -1\end{array}\right]\)