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Consider the following problem:
The total revenue Addison expects from selling rose bouquets in June changes at a rate of 
r(x)=8-0.5 x thousands of dollars (where 
x is the price per bouquet in dollars). When 
x=30, the total expected revenue is 
$2000 dollars. By how much does the total expected revenue change between a selling price of 
$30 and 
$40 ?
Which expression can we use to solve the problem?
Choose 1 answer:
(A) 
int_(30)^(40)r(x)dx
(B) 
2000+int_(30)^(40)r(x)dx
(C) 
2000+int_(30)^(40)r^(')(x)dx
(D) 
int_(30)^(40)r^(')(x)dx

Consider the following problem:\newlineThe total revenue Addison expects from selling rose bouquets in June changes at a rate of r(x)=80.5x r(x)=8-0.5 x thousands of dollars (where x x is the price per bouquet in dollars). When x=30 x=30 , the total expected revenue is $2000 \$ 2000 dollars. By how much does the total expected revenue change between a selling price of $30 \$ 30 and $40 \$ 40 ?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) 3040r(x)dx \int_{30}^{40} r(x) d x \newline(B) 2000+3040r(x)dx 2000+\int_{30}^{40} r(x) d x \newline(C) 2000+3040r(x)dx 2000+\int_{30}^{40} r^{\prime}(x) d x \newline(D) 3040r(x)dx \int_{30}^{40} r^{\prime}(x) d x

Full solution

Q. Consider the following problem:\newlineThe total revenue Addison expects from selling rose bouquets in June changes at a rate of r(x)=80.5x r(x)=8-0.5 x thousands of dollars (where x x is the price per bouquet in dollars). When x=30 x=30 , the total expected revenue is $2000 \$ 2000 dollars. By how much does the total expected revenue change between a selling price of $30 \$ 30 and $40 \$ 40 ?\newlineWhich expression can we use to solve the problem?\newlineChoose 11 answer:\newline(A) 3040r(x)dx \int_{30}^{40} r(x) d x \newline(B) 2000+3040r(x)dx 2000+\int_{30}^{40} r(x) d x \newline(C) 2000+3040r(x)dx 2000+\int_{30}^{40} r^{\prime}(x) d x \newline(D) 3040r(x)dx \int_{30}^{40} r^{\prime}(x) d x
  1. Understand the problem: Understand the problem.\newlineWe need to find the change in total expected revenue as the price per bouquet increases from $30\$30 to $40\$40. The rate of change of revenue with respect to the price is given by the function r(x)=80.5xr(x) = 8 - 0.5x. To find the total change in revenue, we need to integrate this rate of change over the interval from x=30x = 30 to x=40x = 40.
  2. Identify the correct expression: Identify the correct expression to use.\newlineTo find the total change in revenue, we integrate the rate of change function r(x)r(x) over the interval from x=30x = 30 to x=40x = 40. The correct expression to use is the definite integral of r(x)r(x) from 3030 to 4040, which is represented by 3040r(x)dx\int_{30}^{40} r(x) \, dx. This corresponds to option (A).
  3. Evaluate the integral to find the change in revenue: Evaluate the integral to find the change in revenue.\newlineWe calculate the integral of r(x)r(x) from 3030 to 4040.\newline3040r(x)dx=3040(80.5x)dx\int_{30}^{40} r(x) \, dx = \int_{30}^{40} (8 - 0.5x) \, dx\newline=[8x0.25x2]3040= [8x - 0.25x^2]_{30}^{40}\newline=(8(40)0.25(40)2)(8(30)0.25(30)2)= (8(40) - 0.25(40)^2) - (8(30) - 0.25(30)^2)\newline=(320400)(240225)= (320 - 400) - (240 - 225)\newline=80(15)= -80 - (-15)\newline=80+15= -80 + 15\newline=65= -65\newlineThe result is in thousands of dollars, so the change in revenue is 303000.

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