Consider the following problem:The total revenue Addison expects from selling rose bouquets in June changes at a rate of r(x)=8−0.5x thousands of dollars (where x is the price per bouquet in dollars). When x=30, the total expected revenue is $2000 dollars. By how much does the total expected revenue change between a selling price of $30 and $40 ?Which expression can we use to solve the problem?Choose 1 answer:(A) ∫3040r′(x)dx(B) 2000+∫3040r(x)dx(C) 2000+∫3040r′(x)dx(D) ∫3040r(x)dx
Q. Consider the following problem:The total revenue Addison expects from selling rose bouquets in June changes at a rate of r(x)=8−0.5x thousands of dollars (where x is the price per bouquet in dollars). When x=30, the total expected revenue is $2000 dollars. By how much does the total expected revenue change between a selling price of $30 and $40 ?Which expression can we use to solve the problem?Choose 1 answer:(A) ∫3040r′(x)dx(B) 2000+∫3040r(x)dx(C) 2000+∫3040r′(x)dx(D) ∫3040r(x)dx
Integrate rate of change: To find the change in total expected revenue between a selling price of $30 and $40, we need to integrate the rate of change of revenue, r(x), from x=30 to x=40. This will give us the total change in revenue over that interval.
Calculate revenue function: The rate of change of revenue is given by r(x)=8−0.5x. We need to integrate this function from x=30 to x=40 to find the total change in revenue.
Use correct expression: The correct expression to use for this problem is the integral of r(x) from 30 to 40, which is represented by ∫3040r(x)dx. This corresponds to option (D).
Calculate integral: Now we calculate the integral of r(x) from 30 to 40.∫3040(8−0.5x)dx=[8x−0.25x2]3040=(8⋅40−0.25⋅402)−(8⋅30−0.25⋅302)=(320−400)−(240−225)=−80−(−15)=−80+15=−65
Find total revenue change: The total change in expected revenue between a selling price of $30 and $40 is −$65 thousand dollars (since the revenue is given in thousands of dollars).
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