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Consider the following problem:$\newline$The depth of the water in Harsha's bird bath is changing at a rate of $r(t)=0.25 t-0.1$ millimeters per hour (where $t$ is the time in hours). At time $t=0$, the depth of the water is $35$ millimeters. What is the depth of the water at $t=3$ hours?$\newline$Which expression can we use to solve the problem?$\newline$Choose $1$ answer:$\newline$(A) $35+\int_{3}^{3} r(t) d t$$\newline$(B) $35+\int_{3}^{4} r(t) d t$$\newline$(C) $35+\int_{0}^{3} r(t) d t$$\newline$(D) $35+\int_{2}^{3} r(t) d t$