Complete the recursive formula of the geometric sequence {:[-0.3","0.9","-2.7","8.1","dots],[b(1)=],[b(n)=b(n-1)]:}

Given Sequence: We are given the first few terms of a geometric sequence: -0.3, 0.9, -2.7, 8.1, ... To find the recursive formula, we need to determine the common ratio (r) by dividing any term by the previous term. Let's divide the second term by the first term to find r. r = 0.9 / (-0.3) = -3Find Common Ratio: Now that we have the common ratio, we can write the recursive formula. We are given the first term b(1) = -0.3. The recursive formula is b(n) = b(n-1) * r, where r is the common ratio. Substitute r = -3 into the formula. b(n) = b(n-1) * (-3)

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Complete the recursive formula of the geometric sequence

{:[-0.3","0.9","-2.7","8.1","dots],[b(1)=],[b(n)=b(n-1)]:}

Complete the recursive formula of the geometric sequence $\newline$ $\begin{array}{l} -0.3,0.9,-2.7,8.1, \ldots . \\ b(1)=\square \\ b(n)=b(n-1) \cdot \square \end{array}$

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Algebra 1

Write variable expressions for geometric sequences

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Q. Complete the recursive formula of the geometric sequence

\newline

\begin{array}{l} -0.3,0.9,-2.7,8.1, \ldots . \\ b(1)=\square \\ b(n)=b(n-1) \cdot \square \end{array}

Given Sequence: We are given the first few terms of a geometric sequence: $-0.3$ , $0.9$ , $-2.7$ , $8.1$ , ... $\newline$ To find the recursive formula, we need to determine the common ratio ( $r$ ) by dividing any term by the previous term. $\newline$ Let's divide the second term by the first term to find $r$ . $\newline$ $r = \frac{0.9}{-0.3} = -3$
Find Common Ratio: Now that we have the common ratio, we can write the recursive formula. $\newline$ We are given the first term $b(1) = -0.3$ . $\newline$ The recursive formula is $b(n) = b(n-1) \times r$ , where $r$ is the common ratio. $\newline$ Substitute $r = -3$ into the formula. $\newline$ $b(n) = b(n-1) \times (-3)$