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Complete the recursive formula of the arithmetic sequence

{:[-5","-25","-45","-65","dots],[b(1)=],[b(n)=b(n-1)+]:}

Complete the recursive formula of the arithmetic sequence\newline5,25,45,65,.b(1)=b(n)=b(n1)+ \begin{array}{l} -5,-25,-45,-65, \ldots . \\ b(1)=\square \\ b(n)=b(n-1)+\square \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline5,25,45,65,.b(1)=b(n)=b(n1)+ \begin{array}{l} -5,-25,-45,-65, \ldots . \\ b(1)=\square \\ b(n)=b(n-1)+\square \end{array}
  1. Identify First Term: Identify the first term of the sequence. The first term is given as b(1)=5b(1) = -5.
  2. Determine Common Difference: Determine the common difference by subtracting the first term from the second term: 25(5)=25+5=20-25 - (-5) = -25 + 5 = -20.
  3. Verify Consistency: Verify the common difference by subtracting subsequent terms to ensure it is consistent: 45(25)=45+25=20-45 - (-25) = -45 + 25 = -20 and 65(45)=65+45=20-65 - (-45) = -65 + 45 = -20. The common difference is consistent, so it is an arithmetic sequence with a common difference of 20-20.
  4. Write Recursive Formula: Write the recursive formula using the first term and the common difference. The recursive formula for an arithmetic sequence is b(n)=b(n1)+db(n) = b(n-1) + d, where dd is the common difference. Here, b(1)=5b(1) = -5 and d=20d = -20.
  5. Substitute Values: Substitute the values into the recursive formula to get the final expression: b(n)=b(n1)20b(n) = b(n-1) - 20.

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