Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Complete the recursive formula of the arithmetic sequence

{:[-16","-33","-50","-67","dots.],[c(1)=],[c(n)=c(n-1)+]:}

Complete the recursive formula of the arithmetic sequence\newline16,33,50,67,.c(1)=c(n)=c(n1)+ \begin{array}{l} -16,-33,-50,-67, \ldots . \\ c(1)= \square\\ c(n)=c(n-1)+\square \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline16,33,50,67,.c(1)=c(n)=c(n1)+ \begin{array}{l} -16,-33,-50,-67, \ldots . \\ c(1)= \square\\ c(n)=c(n-1)+\square \end{array}
  1. Identify common difference: Identify the common difference in the sequence by subtracting any term from the term that follows it. For instance, subtract 16-16 from 33-33.\newlineCalculation: 33(16)=33+16=17-33 - (-16) = -33 + 16 = -17.\newlineCheck for math errors by verifying with another pair of terms: 50(33)=50+33=17-50 - (-33) = -50 + 33 = -17.
  2. Calculate common difference: Since the common difference is consistent and is 17-17, we can write the recursive formula for the arithmetic sequence as c(n)=c(n1)+dc(n) = c(n-1) + d, where dd is the common difference.\newlineCalculation: d=17d = -17.
  3. Substitute into formula: Substitute the common difference into the recursive formula.\newlineCalculation: c(n)=c(n1)17c(n) = c(n-1) - 17.
  4. Find first term: The first term of the sequence, c(1)c(1), is given as 16-16. This is the base case for the recursive formula.\newlineCalculation: c(1)=16c(1) = -16.

More problems from Write a formula for an arithmetic sequence