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Complete the recursive formula of the arithmetic sequence

{:[-15","-11","-7","-3","dots.],[c(1)=],[c(n)=c(n-1)+]:}

Complete the recursive formula of the arithmetic sequence\newline15,11,7,3,.c(1)=c(n)=c(n1)+ \begin{array}{l} -15,-11,-7,-3, \ldots . \\ c(1)=\square \\ c(n)=c(n-1)+\square \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline15,11,7,3,.c(1)=c(n)=c(n1)+ \begin{array}{l} -15,-11,-7,-3, \ldots . \\ c(1)=\square \\ c(n)=c(n-1)+\square \end{array}
  1. Identify Common Difference: Identify the common difference in the sequence by subtracting any term from the term that follows it. For instance, subtracting the first term from the second term: 11(15)=11+15=4-11 - (-15) = -11 + 15 = 4.
  2. Confirm Consistency: Confirm the common difference by checking if it is consistent between other consecutive terms. For example, subtract the second term from the third term: 7(11)=7+11=4-7 - (-11) = -7 + 11 = 4. The common difference is consistent and is 44.
  3. Write Recursive Formula: Write the recursive formula for the arithmetic sequence. The recursive formula has two parts: the first term and the rule for finding the nnth term from the (n1)(n-1)th term. The first term, c(1)c(1), is given as 15-15. The rule for finding the nnth term is to add the common difference to the (n1)(n-1)th term, which is c(n)=c(n1)+4c(n) = c(n-1) + 4.

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