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Complete the recursive formula of the arithmetic sequence

14,30,46,62,dots". "

{:[d(1)=◻],[d(n)=d(n-1)+]:}

Complete the recursive formula of the arithmetic sequence\newline14,30,46,62,..  14,30,46,62, \ldots \text {.. } \newlined(1)=d(n)=d(n1)+ \begin{array}{l} d(1) = \square \\ d(n) = d(n-1)+\square\\ \end{array}

Full solution

Q. Complete the recursive formula of the arithmetic sequence\newline14,30,46,62,..  14,30,46,62, \ldots \text {.. } \newlined(1)=d(n)=d(n1)+ \begin{array}{l} d(1) = \square \\ d(n) = d(n-1)+\square\\ \end{array}
  1. Calculate Common Difference: To find the recursive formula for the arithmetic sequence, we first need to determine the common difference between consecutive terms. We can do this by subtracting the first term from the second term.\newlineCalculation: 3014=1630 - 14 = 16
  2. Write Recursive Formula: The common difference is 1616. This means that each term is 1616 more than the previous term. We can now write the recursive formula using this common difference.\newlineThe recursive formula will have two parts: the first term and the rule for finding any term after the first.\newlineThe first term, d(1)d(1), is given as 1414.\newlineThe rule for finding any term after the first is to add the common difference to the previous term, which can be written as d(n)=d(n1)+16d(n) = d(n-1) + 16.

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