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At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperatures is 
50^(@) Celsius. This causes the cake to cool and the temperature difference loses 
(1)/(5) of its value every minute.
Write a function that gives the temperature difference in degrees Celsius, 
D(t),t minutes after the cake was put in the cooler.

D(t)=

At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperatures is 50 50^{\circ} Celsius. This causes the cake to cool and the temperature difference loses 15 \frac{1}{5} of its value every minute.\newlineWrite a function that gives the temperature difference in degrees Celsius, D(t),t D(t), t minutes after the cake was put in the cooler.\newlineD(t)= D(t)=\square

Full solution

Q. At the moment a hot cake is put in a cooler, the difference between the cake's and the cooler's temperatures is 50 50^{\circ} Celsius. This causes the cake to cool and the temperature difference loses 15 \frac{1}{5} of its value every minute.\newlineWrite a function that gives the temperature difference in degrees Celsius, D(t),t D(t), t minutes after the cake was put in the cooler.\newlineD(t)= D(t)=\square
  1. Identify Initial Difference: Step 11: Identify the initial temperature difference and the rate at which it decreases. The initial temperature difference is 5050 degrees Celsius, and it loses 15\frac{1}{5} of its value every minute.
  2. Determine Decay Function Form: Step 22: Determine the form of the function that models exponential decay. The general form of an exponential decay function is D(t)=D0×(1r)tD(t) = D_0 \times (1 - r)^t, where D0D_0 is the initial value, rr is the decay rate, and tt is time in minutes.
  3. Plug in Values: Step 33: Plug in the initial temperature difference and the decay rate into the exponential decay function. The initial temperature difference D0D_0 is 5050 degrees Celsius, and the decay rate rr is 1/51/5 or 0.20.2. Therefore, the function becomes D(t)=50×(10.2)tD(t) = 50 \times (1 - 0.2)^t.
  4. Simplify Function: Step 44: Simplify the function. The expression (10.2)(1 - 0.2) is equal to 0.80.8. So, the function simplifies to D(t)=50×0.8tD(t) = 50 \times 0.8^t.
  5. Write Final Function: Step 55: Write the final function. The function that gives the temperature difference in degrees Celsius, D(t)D(t), tt minutes after the cake was put in the cooler is D(t)=50×0.8tD(t) = 50 \times 0.8^t.

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