Q. A rectangular front porch has an area of 60 square feet. Its perimeter is 32 feet. What are the dimensions of the porch?___ feet by ___ feet
Define Area Equation: Let's denote the length of the porch as L feet and the width as W feet. We know that the area (A) of a rectangle is given by the formula A=L×W. We are given that the area is 60 square feet.So, we have the equation:L×W=60
Define Perimeter Equation: We also know that the perimeter P of a rectangle is given by the formula P=2L+2W. We are given that the perimeter is 32 feet.So, we have the equation:2L+2W=32
Simplify Perimeter Equation: To find the dimensions L and W, we need to solve these two equations together. Let's simplify the perimeter equation by dividing all terms by 2 to make it easier to work with:L+W=16
Express W in Terms of L: Now we have a system of two equations:1) L×W=602) L+W=16We can solve this system by expressing one variable in terms of the other using the second equation. Let's express W in terms of L:W=16−L
Substitute W into Area Equation: Substitute W=16−L into the first equation (L×W=60):L×(16−L)=60Expand the equation:16L−L2=60
Rearrange Equation to Quadratic: Rearrange the equation to form a quadratic equation: L2−16L+60=0
Solve Quadratic Equation: Now we need to solve the quadratic equation for L. We can do this by factoring, completing the square, or using the quadratic formula. The equation looks like it can be factored:(L−10)(L−6)=0
Find Possible Values for L: Setting each factor equal to zero gives us the possible values for L:L−10=0 or L−6=0So, L=10 or L=6
Calculate Possible Dimensions: If L=10, then W=16−L=16−10=6. If L=6, then W=16−L=16−6=10. Since a rectangle's length and width are interchangeable, we have two possible sets of dimensions that satisfy both the area and perimeter: 10 feet by 6 feet or 6 feet by 10 feet.
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