A piece of paper is to display 128 square inches of text. If there are to be one-inch margins on both sides and two-inch margins at the bottom and top, what are the dimensions of the smallest piece of paper (by area) that can be used?Choose 1 answer:(A) 8′′×16′′(B) 10′′×15′′(C) 10′′×18′′(D) 10′′×20′′(E) None of these
Q. A piece of paper is to display 128 square inches of text. If there are to be one-inch margins on both sides and two-inch margins at the bottom and top, what are the dimensions of the smallest piece of paper (by area) that can be used?Choose 1 answer:(A) 8′′×16′′(B) 10′′×15′′(C) 10′′×18′′(D) 10′′×20′′(E) None of these
Calculate Side Margins: First, let's calculate the total width of the margins on both sides. Since there's a one-inch margin on each side, that's 1 inch + 1 inch = 2 inches total for the side margins.
Calculate Top and Bottom Margins: Next, calculate the total height of the margins at the bottom and top. There's a two-inch margin at the bottom and top, so that's 2 inches + 2 inches = 4 inches total for the top and bottom margins.
Find Paper Dimensions: Now, we need to add the width of the margins to the width of the text area and the height of the margins to the height of the text area to get the dimensions of the paper. Let's call the width of the text area W and the height H. So the dimensions of the paper would be (W+2) by (H+4).
Calculate Text Area: Since the area of the text is 128 square inches, we have W×H=128. We need to find values of W and H that when multiplied give 128 and, when increased by the margins, give us the smallest possible area for the paper.
Test Option (A): Looking at the answer choices, we can start by testing them to see which one fits our requirements. Let's start with option (A) 8′′×16′′. If we subtract the margins, the text area would be (8−2) inches by (16−4) inches, which is 6 inches by 12 inches. But 6×12=72, not 128.
Test Option (B): Next, let's try option (B) 10′×15′. Subtracting the margins, the text area would be (10−2) inches by (15−4) inches, which is 8 inches by 11 inches. But 8×11=88, which is also not 128.
Test Option (C): Now, let's try option (C) 10′×18′. Subtracting the margins, the text area would be (10−2) inches by (18−4) inches, which is 8 inches by 14 inches. But 8×14=112, which is still not 128.
Test Option (D): Let's try option (D) 10′×20′. Subtracting the margins, the text area would be (10−2) inches by (20−4) inches, which is 8 inches by 16 inches. And 8×16=128, which is correct. So the dimensions of the paper are 10 inches by 20 inches.
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