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A line has a slope of 16\frac{1}{6} and passes through the point (3,8)(-3,-8). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney______=______(x______)y - \_\_\_\_\_\_ = \_\_\_\_\_\_(x - \_\_\_\_\_\_)

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Q. A line has a slope of 16\frac{1}{6} and passes through the point (3,8)(-3,-8). What is its equation in point-slope form?\newlineUse the specified point in your equation. Write your answer using integers, proper fractions, and improper fractions. Simplify all fractions.\newliney______=______(x______)y - \_\_\_\_\_\_ = \_\_\_\_\_\_(x - \_\_\_\_\_\_)
  1. Identify Point-Slope Form: Identify the point-slope form of a linear equation.\newlineThe point-slope form of a linear equation is given by the formula yy1=m(xx1)y - y_1 = m(x - x_1), where mm is the slope of the line and (x1,y1)(x_1, y_1) is a point on the line.
  2. Substitute Slope and Point: Substitute the given slope and point into the point-slope form.\newlineWe are given the slope m=16m = \frac{1}{6} and the point (3,8)(-3, -8). Substituting these values into the point-slope form, we get:\newliney(8)=(16)(x(3))y - (-8) = \left(\frac{1}{6}\right)(x - (-3))
  3. Simplify Equation: Simplify the equation.\newlineSimplifying the equation, we get:\newliney+8=16(x+3)y + 8 = \frac{1}{6}(x + 3)\newlineThis is the equation of the line in point-slope form.

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