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Simplify.
Multiply and remove all perfect squares from inside the square roots. Assume 
x is positive.

2sqrt(7x)*3sqrt(14x^(2))=

Simplify.\newlineMultiply and remove all perfect squares from inside the square roots. Assume \newlinexx is positive.\newline27x314x2=2\sqrt{7x}\cdot3\sqrt{14x^{2}}=

Full solution

Q. Simplify.\newlineMultiply and remove all perfect squares from inside the square roots. Assume \newlinexx is positive.\newline27x314x2=2\sqrt{7x}\cdot3\sqrt{14x^{2}}=
  1. Write expression: Write down the expression to be simplified.\newlineWe have the expression 27x314x22\sqrt{7x}\cdot3\sqrt{14x^{2}}.
  2. Multiply coefficients and radicands: Multiply the coefficients (numbers outside the square roots) and the radicands (expressions inside the square roots) separately.\newlineThe coefficients are 22 and 33, so multiplying them gives us 2×3=62 \times 3 = 6.\newlineThe radicands are 7x7x and 14x214x^2, so multiplying them gives us 7x×14x2=98x37x \times 14x^2 = 98x^3.\newlineSo now we have 698x36\sqrt{98x^3}.
  3. Factor radicand: Factor the radicand to identify perfect squares.\newlineThe number 9898 can be factored into 2×492 \times 49, and 4949 is a perfect square (727^2). The x3x^3 can be written as x2×xx^2 \times x, where x2x^2 is a perfect square.\newlineSo we can rewrite the radicand as 2×72×x2×x2 \times 7^2 \times x^2 \times x.
  4. Take square root of perfect squares: Take the square root of the perfect squares.\newlineThe square root of 727^2 is 77, and the square root of x2x^2 is xx.\newlineSo we can take these outside the square root, giving us 67x2x6 \cdot 7 \cdot x \cdot \sqrt{2x}.
  5. Multiply numbers and variables: Multiply the numbers and variables outside the square root.\newlineMultiplying 66, 77, and xx gives us 42x42x.\newlineSo the expression simplifies to 42x2x42x\sqrt{2x}.

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