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Multiply and simplify the following complex numbers:

(-3-i)*(3+i)

Multiply and simplify the following complex numbers:\newline(3i)(3+i) (-3-i) \cdot(3+i)

Full solution

Q. Multiply and simplify the following complex numbers:\newline(3i)(3+i) (-3-i) \cdot(3+i)
  1. Apply distributive property: Apply the distributive property (also known as the FOIL method for binomials) to multiply the two complex numbers.\newline(3i)(3+i)=(3)(3)+(3)(i)+(i)(3)+(i)(i)(-3-i)*(3+i) = (-3)*(3) + (-3)*(i) + (-i)*(3) + (-i)*(i)
  2. Multiply terms: Multiply each term.\newline(3)(3)=9(-3)\cdot(3) = -9\newline(3)(i)=3i(-3)\cdot(i) = -3i\newline(i)(3)=3i(-i)\cdot(3) = -3i\newline(i)(i)=i2(-i)\cdot(i) = -i^2
  3. Evaluate i2i^2: Remember that i2i^2 is equal to 1-1.\newlinei2=(1)=1-i^2 = -(-1) = 1
  4. Combine like terms: Combine like terms.\newline9+(3i)+(3i)+1=9+13i3i-9 + (-3i) + (-3i) + 1 = -9 + 1 - 3i - 3i
  5. Simplify the expression: Simplify the expression by adding/subtracting the real parts and the imaginary parts.\newline9+13i3i=86i-9 + 1 - 3i - 3i = -8 - 6i

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