A third degree polynomial function y=g(x) is defined so that g(32)=0 and g(0)=5. Which of the following must be a factor of g ?Choose 1 answer:(A) x−5(B) x+5(C) 3x−2(D) 3x+2
Q. A third degree polynomial function y=g(x) is defined so that g(32)=0 and g(0)=5. Which of the following must be a factor of g ?Choose 1 answer:(A) x−5(B) x+5(C) 3x−2(D) 3x+2
Given information: We are given that g(32)=0. This means that when x equals 32, the polynomial function g(x) equals zero. This implies that x−32 is a root of the polynomial, and therefore (x−32) must be a factor of g(x).
Finding the factor: To express the factor with integer coefficients, we can multiply the factor x−32 by 3 to clear the fraction. This gives us 3(x−32)=3x−2. Therefore, (3x−2) must be a factor of g(x).
Matching the factor: Now we look at the answer choices to see which one matches the factor we found. The factor we found is (3x−2), which corresponds to answer choice (C).
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