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A third degree polynomial function 
y=g(x) is defined so that 
g((2)/(3))=0 and 
g(0)=5. Which of the following must be a factor of 
g ?
Choose 1 answer:
(A) 
x-5
(B) 
x+5
(c) 
3x-2
(D) 
3x+2

A third degree polynomial function y=g(x) y=g(x) is defined so that g(23)=0 g\left(\frac{2}{3}\right)=0 and g(0)=5 g(0)=5 . Which of the following must be a factor of g g ?\newlineChoose 11 answer:\newline(A) x5 x-5 \newline(B) x+5 x+5 \newline(C) 3x2 3 x-2 \newline(D) 3x+2 3 x+2

Full solution

Q. A third degree polynomial function y=g(x) y=g(x) is defined so that g(23)=0 g\left(\frac{2}{3}\right)=0 and g(0)=5 g(0)=5 . Which of the following must be a factor of g g ?\newlineChoose 11 answer:\newline(A) x5 x-5 \newline(B) x+5 x+5 \newline(C) 3x2 3 x-2 \newline(D) 3x+2 3 x+2
  1. Given information: We are given that g(23)=0g\left(\frac{2}{3}\right)=0. This means that when xx equals 23\frac{2}{3}, the polynomial function g(x)g(x) equals zero. This implies that x23x - \frac{2}{3} is a root of the polynomial, and therefore (x23)(x - \frac{2}{3}) must be a factor of g(x)g(x).
  2. Finding the factor: To express the factor with integer coefficients, we can multiply the factor x23x - \frac{2}{3} by 33 to clear the fraction. This gives us 3(x23)=3x23(x - \frac{2}{3}) = 3x - 2. Therefore, (3x2)(3x - 2) must be a factor of g(x)g(x).
  3. Matching the factor: Now we look at the answer choices to see which one matches the factor we found. The factor we found is (3x2)(3x - 2), which corresponds to answer choice (C)(C).

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