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(x-3)^(2)+(y-1)^(2)=16
A circle in the 
xy-plane is represented by the given equation. If the circle is shifted 3 units to the left and 4 units up, which of the following equations represents the shifted circle?
Choose 1 answer:
(A) 
x^(2)+(y-5)^(2)=16
(B) 
x^(2)+(y+3)^(2)=16
(C) 
(x-6)^(2)+(y-5)^(2)=16
(D) 
(x-6)^(2)+(y+3)^(2)=16

(x3)2+(y1)2=16 (x-3)^{2}+(y-1)^{2}=16 \newlineA circle in the xy x y -plane is represented by the given equation. If the circle is shifted 33 units to the left and 44 units up, which of the following equations represents the shifted circle?\newlineChoose 11 answer:\newline(A) x2+(y5)2=16 x^{2}+(y-5)^{2}=16 \newline(B) x2+(y+3)2=16 x^{2}+(y+3)^{2}=16 \newline(C) (x6)2+(y5)2=16 (x-6)^{2}+(y-5)^{2}=16 \newline(D) (x6)2+(y+3)2=16 (x-6)^{2}+(y+3)^{2}=16

Full solution

Q. (x3)2+(y1)2=16 (x-3)^{2}+(y-1)^{2}=16 \newlineA circle in the xy x y -plane is represented by the given equation. If the circle is shifted 33 units to the left and 44 units up, which of the following equations represents the shifted circle?\newlineChoose 11 answer:\newline(A) x2+(y5)2=16 x^{2}+(y-5)^{2}=16 \newline(B) x2+(y+3)2=16 x^{2}+(y+3)^{2}=16 \newline(C) (x6)2+(y5)2=16 (x-6)^{2}+(y-5)^{2}=16 \newline(D) (x6)2+(y+3)2=16 (x-6)^{2}+(y+3)^{2}=16
  1. Original Circle Transformation: Original circle: (x3)2+(y1)2=16(x-3)^2 + (y-1)^2 = 16.\newlineShift 33 units left: replace xx with (x+3)(x+3).
  2. Shift Left and Up: Shift 44 units up: replace yy with (y4)(y-4).
  3. New Equation Formation: New equation: ((x+3)3)2+((y4)1)2=16((x+3)-3)^2 + ((y-4)-1)^2 = 16.
  4. Simplification: Simplify: (x)2+(y5)2=16(x)^2 + (y-5)^2 = 16.
  5. Answer Choice Matching: Match with answer choices: (A) x2+(y5)2=16x^2 + (y-5)^2 = 16.

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