{:[{[f(1)=-3],[f(n)=2*f(n-1)+1]:}],[f(2)=]:}

Find f(2): First, we need to find f(2) using the given recursive formula. We know f(1) = -3. Use Recursive Formula: The formula given is f(n) = 2*f(n-1) + 1. So, let's plug in n = 2. f(2) = 2*f(1) + 1 Substitute f(1): Substitute f(1) = -3 into the equation: f(2) = 2*(-3) + 1 Calculate: Calculate: f(2) = -6 + 1 = -5

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$\begin{cases} f(1)=-3 \ f(n)=2\cdot f(n-1)+1 \end{cases}$ , $f(2)=$

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Calculus

Find higher derivatives of rational and radical functions

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\begin{cases} f(1)=-3 \ f(n)=2\cdot f(n-1)+1 \end{cases}

f(2)=

Find $f(2)$ : $\newline$ First, we need to find $f(2)$ using the given recursive formula. We know $f(1) = -3$ .
Use Recursive Formula: $\newline$ The formula given is $f(n) = 2 \cdot f(n-1) + 1$ . So, let's plug in $n = 2$ . $\newline$ $f(2) = 2 \cdot f(1) + 1$
Substitute $f(1)$ : Substitute $f(1) = -3$ into the equation: $f(2) = 2 \times (-3) + 1$
Calculate: $\newline$ Calculate: $\newline$ $f(2) = -6 + 1 = -5$