(3y−2)(y+a)=3y2+bzIf the given equation is true for all values of y, where a and b are constants, which of the following is the value of b ?Choose 1 answer:(A) −38(B) 12(C) 34(D) 36
Q. (3y−2)(y+a)=3y2+bzIf the given equation is true for all values of y, where a and b are constants, which of the following is the value of b ?Choose 1 answer:(A) −38(B) 12(C) 34(D) 36
Expand and Compare: We need to expand the left side of the equation (3y−2)(y+a) to compare it with the right side 3y2+bz.(3y−2)(y+a)=3y(y)+3y(a)−2(y)−2(a)
Simplify Expression: Now we simplify the expression by multiplying the terms.3y(y)+3y(a)−2(y)−2(a)=3y2+3ay−2y−2a
Comparison with Right Side: We compare the simplified expression with the right side of the given equation.3y2+3ay−2y−2a=3y2+bz
Coefficient Comparison for y: Since the equation is true for all values of y, the coefficients of the corresponding terms on both sides must be equal. This means that the coefficient of y on the left side (3a−2) must be equal to the coefficient of y on the right side, which is 0 (since there is no y term on the right side).3a−2=0
Solve for a: We solve for a.3a−2=03a=2a=32
Constant Term Comparison: Now we look for the constant term on the left side, which is −2a, and compare it with the constant term on the right side, which is bz. −2a=bz
Substitute Value of a: We substitute the value of a into the equation.−2(32)=bz−34=bz
Determine Coefficient for b: Since there is no z term on the left side of the original equation, the coefficient of z on the right side must be 0. Therefore, b must be 0. bz=0 b=0
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