Resources
Testimonials
Plans
Sign in
Sign up
Resources
Testimonials
Plans
Home
Math Problems
Precalculus
Use normal distributions to approximate binomial distributions
If
f
(
x
)
f(x)
f
(
x
)
is an exponential function where
f
(
−
1.5
)
=
26
f(-1.5)=26
f
(
−
1.5
)
=
26
and
f
(
5.5
)
=
7
f(5.5)=7
f
(
5.5
)
=
7
, then find the value of
f
(
10
)
f(10)
f
(
10
)
, to the nearest hundredth.
Get tutor help
A survey found that women spend, on average,
$
146.21
\$ 146.21
$146.21
on beauty products during the summer months, with a standard deviation of
$
29.44
\$ 29.44
$29.44
. What percentage of women spend less than
$
160
\$ 160
$160
? Round to the nearest hundredth. Assume the distribution is normal.
Get tutor help
A study of a local high school tried to determine the mean amount of money that each student had saved. The study surveyed a random sample of
65
65
65
students in the high school and found a mean savings of
2700
2700
2700
dollars with a standard deviation of
700
700
700
dollars. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest whole number. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study was commissioned to find the mean weight of the residents in certain town. The study examined a random sample of
76
76
76
residents and found the mean weight to be
198
198
198
pounds with a standard deviation of
22
22
22
pounds. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest tenth. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study of a local high school tried to determine the mean amount of money that each student had saved. The study surveyed a random sample of
32
32
32
students in the high school and found a mean savings of
4300
4300
4300
dollars with a standard deviation of
800
800
800
dollars. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest whole number. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study by the department of education of a certain state was trying to determine the mean SAT scores of the graduating high school seniors. The study examined the scores of a random sample of
178
178
178
graduating seniors and found the mean score to be
487
487
487
with a standard deviation of
119
119
119
. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest tenth. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study was commissioned to find the mean weight of the residents in certain town. The study examined a random sample of
142
142
142
residents and found the mean weight to be
164
164
164
pounds with a standard deviation of
26
26
26
pounds. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest tenth. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study of a local high school tried to determine the mean amount of money that each student had saved. The study surveyed a random sample of
60
60
60
students in the high school and found a mean savings of
2500
2500
2500
dollars with a standard deviation of
1400
1400
1400
dollars. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest whole number. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study of a local high school tried to determine the mean amount of money that each student had saved. The study surveyed a random sample of
74
74
74
students in the high school and found a mean savings of
4500
4500
4500
dollars with a standard deviation of
1300
1300
1300
dollars. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest whole number. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study by the department of education of a certain state was trying to determine the mean SAT scores of the graduating high school seniors. The study examined the scores of a random sample of
98
98
98
graduating seniors and found the mean score to be
492
492
492
with a standard deviation of
117
117
117
. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest tenth. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study of a local high school tried to determine the mean amount of money that each student had saved. The study surveyed a random sample of
59
59
59
students in the high school and found a mean savings of
4000
4000
4000
dollars with a standard deviation of
1000
1000
1000
dollars. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest whole number. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study by the department of education of a certain state was trying to determine the mean SAT scores of the graduating high school seniors. The study examined the scores of a random sample of
199
199
199
graduating seniors and found the mean score to be
537
537
537
with a standard deviation of
82
82
82
. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest tenth. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study of a local high school tried to determine the mean amount of money that each student had saved. The study surveyed a random sample of
71
71
71
students in the high school and found a mean savings of
2600
2600
2600
dollars with a standard deviation of
1500
1500
1500
dollars. At the
95
%
95 \%
95%
confidence level, use the normal distribution/empirical rule to estimate the margin of error for the mean, rounding to the nearest whole number. (Do not write
±
\pm
±
).
\newline
Answer:
Get tutor help
A study of a local high school tried to determine the mean amount of money that each student had saved. The study surveyed a random sample of
32
32
32
students in the high school and found a mean savings of
2900
2900
2900
dollars with a standard deviation of
1300
1300
1300
dollars. Use the normal distribution/empirical rule to estimate a
95
%
95 \%
95%
confidence interval for the mean, rounding all values to the nearest whole number.
Get tutor help
A study was commissioned to find the mean weight of the residents in certain town. The study examined a random sample of
113
113
113
residents and found the mean weight to be
159
159
159
pounds with a standard deviation of
34
34
34
pounds. Use the normal distribution/empirical rule to estimate a
95
%
95 \%
95%
confidence interval for the mean, rounding all values to the nearest tenth.
Get tutor help
A study was commissioned to find the mean weight of the residents in certain town. The study examined a random sample of
133
133
133
residents and found the mean weight to be
165
165
165
pounds with a standard deviation of
25
25
25
pounds. Use the normal distribution/empirical rule to estimate a
95
%
95 \%
95%
confidence interval for the mean, rounding all values to the nearest tenth.
Get tutor help
A study was commissioned to find the mean weight of the residents in certain town. The study examined a random sample of
36
36
36
residents and found the mean weight to be
182
182
182
pounds with a standard deviation of
29
29
29
pounds. Use the normal distribution/empirical rule to estimate a
95
%
95 \%
95%
confidence interval for the mean, rounding all values to the nearest tenth.
Get tutor help
$
400
\$ 400
$400
is invested in an account earning
9
9
9
.
8
8
8
\% interest (APR), compounded daily. Write a function showing the value of the account after
t
t
t
years, where the annual growth rate can be found from a constant in the function. Round all coefficients in the function to four decimal places. Also, determine the percentage of growth per year (APY), to the nearest hundredth of a percent.
Get tutor help
