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Math Problems
Grade 8
Solve equations with the distributive property
Solve.
\newline
−
7
(
2
3
)
+
(
−
5
(
1
2
)
)
+
8
(
3
4
)
=
-7\left(\frac{2}{3}\right)+\left(-5\left(\frac{1}{2}\right)\right)+8\left(\frac{3}{4}\right)=
−
7
(
3
2
)
+
(
−
5
(
2
1
)
)
+
8
(
4
3
)
=
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Solve.
\newline
−
7
(
2
3
)
+
(
−
5
(
1
2
)
)
+
8
(
3
4
)
=
-7\left(\frac{2}{3}\right)+\left(-5\left(\frac{1}{2}\right)\right)+8\left(\frac{3}{4}\right)=
−
7
(
3
2
)
+
(
−
5
(
2
1
)
)
+
8
(
4
3
)
=
□
\square
□
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Simplify the equation :
15
(
y
−
4
)
−
2
(
y
−
9
)
+
5
(
y
+
6
)
=
0
15(y-4)-2(y-9)+5(y+6)=0
15
(
y
−
4
)
−
2
(
y
−
9
)
+
5
(
y
+
6
)
=
0
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Solve for
z
z
z
.
\newline
–
(
z
+
–
9
)
=
5
–(z + –9) = 5
–
(
z
+
–9
)
=
5
\newline
z
=
z =
z
=
_____
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Solve for
q
q
q
.
\newline
5
=
2
(
q
+
2
)
−
3
5 = 2(q + 2) - 3
5
=
2
(
q
+
2
)
−
3
\newline
q
=
q =
q
=
_____
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Solve for
v
v
v
.
\newline
−
2
(
v
+
−
7
)
=
6
-2(v + -7) = 6
−
2
(
v
+
−
7
)
=
6
\newline
v
=
v =
v
=
_____
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Solve for
y
y
y
.
\newline
–
(
y
+
1
)
=
–
5
–(y + 1) = –5
–
(
y
+
1
)
=
–5
\newline
y
=
y =
y
=
_____
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Solve for
j
j
j
.
\newline
6
=
3
(
j
−
7
)
−
(
−
6
)
6 = 3(j - 7) - (-6)
6
=
3
(
j
−
7
)
−
(
−
6
)
\newline
j
=
j =
j
=
_____
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Solve for
w
w
w
.
\newline
2
(
w
+
2
)
−
2
=
8
2(w + 2) − 2 = 8
2
(
w
+
2
)
−2
=
8
\newline
w
=
w =
w
=
_____
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Solve for
d
d
d
.
\newline
−
2
(
d
+
−
9
)
+
−
4
=
6
-2(d + -9) + -4 = 6
−
2
(
d
+
−
9
)
+
−
4
=
6
\newline
d
=
d =
d
=
_____
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Solve for
c
c
c
.
\newline
−
2
(
c
−
7
)
=
4
-2(c - 7) = 4
−
2
(
c
−
7
)
=
4
\newline
c
=
c =
c
=
_____
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Solve for
q
q
q
.
\newline
2
(
q
+
7
)
−
3
=
3
2(q + 7) - 3 = 3
2
(
q
+
7
)
−
3
=
3
\newline
q
=
q =
q
=
_____
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Solve for
q
q
q
.
\newline
8
=
2
(
q
−
5
)
8 = 2(q - 5)
8
=
2
(
q
−
5
)
\newline
q
=
q =
q
=
_
_
_
_
\_\_\_\_
____
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Solve for
m
m
m
.
\newline
2
(
m
−
7
)
−
1
=
−
1
2(m - 7) - 1 = -1
2
(
m
−
7
)
−
1
=
−
1
\newline
m
=
m =
m
=
_____
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Solve for
s
s
s
.
\newline
−
3
(
s
−
7
)
=
−
6
-3(s - 7) = -6
−
3
(
s
−
7
)
=
−
6
\newline
s
=
s =
s
=
_____
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Solve for
p
p
p
.
\newline
3
(
p
−
8
)
−
3
=
3
3(p - 8) - 3 = 3
3
(
p
−
8
)
−
3
=
3
\newline
p
=
p =
p
=
_
_
_
_
_
\_\_\_\_\_
_____
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Solve for
f
f
f
.
\newline
−
6
=
−
(
f
+
−
8
)
+
−
6
-6 = -(f + -8) + -6
−
6
=
−
(
f
+
−
8
)
+
−
6
\newline
f
=
f =
f
=
_____
Get tutor help
Solve for
q
q
q
.
\newline
2
(
q
+
5
)
−
9
=
−
1
2(q + 5) - 9 = -1
2
(
q
+
5
)
−
9
=
−
1
\newline
q
=
_
_
_
_
q = \_\_\_\_
q
=
____
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Solve for
n
n
n
.
\newline
2
(
n
−
4
)
−
1
=
7
2(n - 4) - 1 = 7
2
(
n
−
4
)
−
1
=
7
\newline
n
=
n =
n
=
_
_
_
_
_
\_\_\_\_\_
_____
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Solve for
c
c
c
.
\newline
2
(
c
+
9
)
+
−
4
=
−
2
2(c + 9) + -4 = -2
2
(
c
+
9
)
+
−
4
=
−
2
\newline
c
=
c =
c
=
_____
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Solve for
f
f
f
.
\newline
10
=
3
(
f
+
1
)
+
1
10 = 3(f + 1) + 1
10
=
3
(
f
+
1
)
+
1
\newline
f
=
f =
f
=
_____
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Solve for
q
q
q
.
\newline
2
(
q
+
1
)
−
8
=
2
2(q + 1) - 8 = 2
2
(
q
+
1
)
−
8
=
2
\newline
q
q
q
=___________
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Solve for
b
b
b
.
\newline
−
2
(
b
+
5
)
+
8
=
8
-2(b + 5) + 8 = 8
−
2
(
b
+
5
)
+
8
=
8
\newline
b
=
b =
b
=
_
_
_
_
_
\_\_\_\_\_
_____
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Solve
5
d
+
6
−
2
d
−
3
=
0
\frac{5}{d+6}-\frac{2}{d-3}=0
d
+
6
5
−
d
−
3
2
=
0
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2
(
x
+
1
)
3
=
1
\frac{2(x+1)}{3} = 1
3
2
(
x
+
1
)
=
1
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b)
16
−
(
r
+
2
)
=
10
+
3
(
r
−
7
)
⇒
16-(r+2)=10+3(r-7) \Rightarrow
16
−
(
r
+
2
)
=
10
+
3
(
r
−
7
)
⇒
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10
x
+
50
(
19
−
x
)
=
350
10x+50(19-x)=350
10
x
+
50
(
19
−
x
)
=
350
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6
(
q
+
3
)
+
8
≥
2
6(q+3)+8 \geq 2
6
(
q
+
3
)
+
8
≥
2
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Solve for
r
r
r
.
\newline
–
(
r
−
4
)
=
–
5
\text{–}(r - 4) = \text{–}5
–
(
r
−
4
)
=
–
5
\newline
r
=
r =
r
=
‾
\underline{\hspace{2em}}
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Solve for
r
r
r
.
\newline
2
(
r
+
7
)
=
−
2
2(r + 7) = -2
2
(
r
+
7
)
=
−
2
\newline
r
=
r =
r
=
_____
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Solve for
r
r
r
.
\newline
3
(
r
−
7
)
=
3
3(r - 7) = 3
3
(
r
−
7
)
=
3
\newline
r
=
r =
r
=
_____
Get tutor help
Solve for
f
f
f
.
\newline
3
(
f
−
7
)
=
3
3(f - 7) = 3
3
(
f
−
7
)
=
3
\newline
f
=
f =
f
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Solve for
y
y
y
.
\newline
2
(
y
+
10
)
=
10
2(y + 10) = 10
2
(
y
+
10
)
=
10
\newline
y
=
y =
y
=
_____
Get tutor help
Solve for
m
m
m
.
\newline
3
(
m
−
5
)
=
9
3(m - 5) = 9
3
(
m
−
5
)
=
9
\newline
m
=
m =
m
=
_____
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Solve for
t
t
t
.
\newline
−
2
=
2
(
t
+
−
5
)
-2 = 2(t + -5)
−
2
=
2
(
t
+
−
5
)
Get tutor help
Solve for
r
r
r
.
\newline
2
(
r
+
1
)
=
10
2(r + 1) = 10
2
(
r
+
1
)
=
10
\newline
r
=
r =
r
=
_____
Get tutor help
Solve for
c
c
c
.
\newline
2
(
c
+
−
10
)
=
−
2
2(c + -10) = -2
2
(
c
+
−
10
)
=
−
2
\newline
c
=
c =
c
=
_____
Get tutor help
Solve for
n
n
n
.
\newline
–
(
n
−
6
)
=
–
3
\text{–}(n − 6) = \text{–}3
–
(
n
−6
)
=
–
3
\newline
n
=
n =
n
=
____
Get tutor help
Solve for
x
x
x
.
\newline
5
3
−
1
3
x
=
2
\frac{5}{3}-\frac{1}{3 x}=2
3
5
−
3
x
1
=
2
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
.
\newline
8
3
−
x
+
8
3
x
=
3
\frac{8}{3}-\frac{x+8}{3 x}=3
3
8
−
3
x
x
+
8
=
3
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
.
\newline
9
5
−
8
5
x
=
2
\frac{9}{5}-\frac{8}{5 x}=2
5
9
−
5
x
8
=
2
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for
x
x
x
.
\newline
3
x
−
7
x
−
7
8
x
=
3
8
\frac{3 x-7}{x}-\frac{7}{8 x}=\frac{3}{8}
x
3
x
−
7
−
8
x
7
=
8
3
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for
x
\mathrm{x}
x
:
\newline
5
x
+
36
−
8
=
−
4
\sqrt{5 x+36}-8=-4
5
x
+
36
−
8
=
−
4
\newline
Answer:
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3
(
x
−
2
)
+
2
(
3
−
x
)
=
1
3(x-2)+2(3-x)=1
3
(
x
−
2
)
+
2
(
3
−
x
)
=
1
Get tutor help
Solve for
u
u
u
.
\newline
u
−
3
4
=
8
3
5
u-\frac{3}{4}=8 \frac{3}{5}
u
−
4
3
=
8
5
3
Get tutor help
Solve for
x
\mathrm{x}
x
.
\newline
3
x
+
8
4
=
x
−
1
9
\frac{3 x+8}{4}=\frac{x-1}{9}
4
3
x
+
8
=
9
x
−
1
\newline
Answer:
Get tutor help
Solve for
x
\mathrm{x}
x
.
\newline
8
x
+
8
=
3
5
x
+
3
\frac{8}{x+8}=\frac{3}{5 x+3}
x
+
8
8
=
5
x
+
3
3
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
x
−
3
4
+
1
10
=
x
+
7
20
\frac{x-3}{4}+\frac{1}{10}=\frac{x+7}{20}
4
x
−
3
+
10
1
=
20
x
+
7
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
2
x
+
7
8
+
2
x
−
7
40
=
−
2
\frac{2 x+7}{8}+\frac{2 x-7}{40}=-2
8
2
x
+
7
+
40
2
x
−
7
=
−
2
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
8
7
+
x
−
5
42
=
2
x
+
3
\frac{8}{7}+\frac{x-5}{42}=2 x+3
7
8
+
42
x
−
5
=
2
x
+
3
\newline
Answer:
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1
2
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