Solve for x. (2x+7)/(8)+(2x-7)/(40)=-2 Answer:

Find Common Denominator: Find a common denominator for the fractions to combine them. The common denominator for 8 and 40 is 40. Multiply the first fraction by 5/5 to get the common denominator. (2x+7)/(8) * (5/5) + (2x-7)/(40) = -2 (10x+35)/(40) + (2x-7)/(40) = -2Combine Fractions: Combine the fractions now that they have a common denominator. (10x+35+2x-7)/(40) = -2 (12x+28)/(40) = -2Eliminate Denominator: Multiply both sides by 40 to eliminate the denominator. 40 * ((12x+28)/(40)) = 40 * (-2) 12x + 28 = -80Isolate x Term: Subtract 28 from both sides to isolate the term with x. 12x + 28 - 28 = -80 - 28 12x = -108Solve for x: Divide both sides by 12 to solve for x. 12x / 12 = -108 / 12 x = -9

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(2x+7)/(8)+(2x-7)/(40)=-2
Answer:

Solve for $\mathrm{x}$ . $\newline$ $\frac{2 x+7}{8}+\frac{2 x-7}{40}=-2$ $\newline$ Answer:

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Math Problems

Grade 8

Solve equations with the distributive property

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Q. Solve for

\mathrm{x}

\newline

\frac{2 x+7}{8}+\frac{2 x-7}{40}=-2

\newline

Answer:

Find Common Denominator: Find a common denominator for the fractions to combine them. $\newline$ The common denominator for $8$ and $40$ is $40$ . Multiply the first fraction by $\frac{5}{5}$ to get the common denominator. $\newline$ $\frac{2x+7}{8} \times \frac{5}{5} + \frac{2x-7}{40} = -2$ $\newline$ $\frac{10x+35}{40} + \frac{2x-7}{40} = -2$
Combine Fractions: Combine the fractions now that they have a common denominator. $\newline$ $(10x+35+2x-7)/(40) = -2$ $\newline$ $(12x+28)/(40) = -2$
Eliminate Denominator: Multiply both sides by $40$ to eliminate the denominator. $\newline$ $40 \times \left(\frac{12x+28}{40}\right) = 40 \times (-2)$ $\newline$ $12x + 28 = -80$
Isolate x Term: Subtract $28$ from both sides to isolate the term with $x$ . $\newline$ $12x + 28 - 28 = -80 - 28$ $\newline$ $12x = -108$
Solve for x: Divide both sides by $12$ to solve for x. $\newline$ $\frac{12x}{12} = \frac{-108}{12}$ $\newline$ $x = -9$