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Math Problems
Grade 7
Solve two-step equations with parentheses
f(
1
1
1
) =
72
72
72
\newline
f(n) = f(n
−
1
-1
−
1
) +
9
9
9
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Solve for
z
z
z
.
\newline
3
(
z
−
13
)
=
15
3(z - 13) = 15
3
(
z
−
13
)
=
15
\newline
z
=
z =
z
=
_____
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Solve for
n
n
n
.
\newline
4
(
n
+
2
)
=
20
4(n + 2) = 20
4
(
n
+
2
)
=
20
\newline
n
=
n =
n
=
_
_
_
_
\_\_\_\_
____
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Solve for
z
z
z
.
\newline
3
(
z
−
12
)
=
12
3(z - 12) = 12
3
(
z
−
12
)
=
12
\newline
z
=
z =
z
=
_____
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Solve for
g
g
g
.
\newline
18
=
3
(
g
−
9
)
18 = 3(g - 9)
18
=
3
(
g
−
9
)
\newline
g
=
g =
g
=
_
_
_
_
\_\_\_\_
____
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Solve for
v
v
v
.
\newline
12
=
2
(
v
+
1
)
12 = 2(v + 1)
12
=
2
(
v
+
1
)
\newline
v
=
v =
v
=
_
_
_
_
\_\_\_\_
____
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Solve for
h
h
h
.
\newline
4
(
h
−
15
)
=
16
4(h - 15) = 16
4
(
h
−
15
)
=
16
\newline
h
=
h =
h
=
_
_
_
_
_
\_\_\_\_\_
_____
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Solve for
y
y
y
.
\newline
14
=
2
(
y
−
8
)
14 = 2(y − 8)
14
=
2
(
y
−8
)
\newline
y
=
y =
y
=
_
_
_
_
\_\_\_\_
____
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Solve for
p
p
p
.
\newline
18
=
3
(
p
+
1
)
18 = 3(p + 1)
18
=
3
(
p
+
1
)
\newline
p
=
p =
p
=
_____
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Solve for
d
d
d
.
\newline
4
(
d
+
1
)
=
16
4(d + 1) = 16
4
(
d
+
1
)
=
16
\newline
d
=
d =
d
=
_
_
_
_
\_\_\_\_
____
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Solve for
m
m
m
.
\newline
2
(
m
+
2
)
=
20
2(m + 2) = 20
2
(
m
+
2
)
=
20
\newline
m
=
m =
m
=
_
_
_
_
\_\_\_\_
____
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Solve for
b
b
b
.
\newline
2
(
b
−
11
)
=
8
2(b - 11) = 8
2
(
b
−
11
)
=
8
\newline
b
=
b =
b
=
_
_
_
_
\_\_\_\_
____
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Solve for
p
p
p
.
\newline
3
(
p
−
16
)
=
9
3(p - 16) = 9
3
(
p
−
16
)
=
9
\newline
p
=
p =
p
=
_____
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Solve for
f
f
f
.
\newline
3
(
f
−
9
)
=
18
3(f - 9) = 18
3
(
f
−
9
)
=
18
\newline
f
=
f =
f
=
_
_
_
_
_
\_\_\_\_\_
_____
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Solve for
d
d
d
.
\newline
18
=
3
(
d
+
2
)
18 = 3(d + 2)
18
=
3
(
d
+
2
)
\newline
d
=
d =
d
=
_____
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Solve for
j
j
j
.
\newline
16
=
4
(
j
−
13
)
16 = 4(j - 13)
16
=
4
(
j
−
13
)
\newline
j
=
j =
j
=
_____
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Solve for
g
g
g
.
\newline
2
(
g
−
13
)
=
10
2(g - 13) = 10
2
(
g
−
13
)
=
10
\newline
g
=
g =
g
=
_
_
_
_
_
\_\_\_\_\_
_____
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Solve for
w
w
w
.
\newline
2
(
w
−
10
)
=
12
2(w - 10) = 12
2
(
w
−
10
)
=
12
\newline
w
=
w =
w
=
_
_
_
_
\_\_\_\_
____
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Solve for
g
g
g
.
\newline
15
=
3
(
g
−
15
)
15 = 3(g - 15)
15
=
3
(
g
−
15
)
\newline
g
=
g =
g
=
_
_
_
_
\_\_\_\_
____
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Solve for
m
m
m
.
\newline
3
(
m
−
17
)
=
6
3(m - 17) = 6
3
(
m
−
17
)
=
6
\newline
m
=
m =
m
=
_____
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Solve for
b
b
b
.
\newline
4
=
2
(
b
−
14
)
4 = 2(b − 14)
4
=
2
(
b
−14
)
\newline
b
=
b =
b
=
_____
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Solve for
w
w
w
.
\newline
3
(
2
w
+
5
)
=
33
3(2 w+5)=33
3
(
2
w
+
5
)
=
33
\newline
Simplify your answer as much as possible
\newline
w
=
w=
w
=
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Solve for
w
w
w
.
\newline
3
(
2
w
+
5
)
=
33
3(2w+5)=33
3
(
2
w
+
5
)
=
33
\newline
Simplify your answer as much as possible.
\newline
w
=
w=
w
=
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Solve the equation
5
(
2
x
+
1
)
=
25
5(2x+1) = 25
5
(
2
x
+
1
)
=
25
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5
(
2
x
+
1
)
=
35
5(2x+1) = 35
5
(
2
x
+
1
)
=
35
Find
x
x
x
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7
(
3
y
+
4
)
=
21
7(3 y+4)=21
7
(
3
y
+
4
)
=
21
Find
y
y
y
value.
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Find
U
1
,
U
2
,
U
3
,
U
4
U_{1}, U_{2}, U_{3}, U_{4}
U
1
,
U
2
,
U
3
,
U
4
.
\newline
U
1
+
U
2
+
U
3
=
220
v
U
1
+
U
4
=
200
v
U
2
+
U
3
=
140
v
U
3
+
U
4
=
160
v
\begin{array}{l}U_{1}+U_{2}+U_{3}=220 v \\ U_{1}+U_{4}=200 v \\ U_{2}+U_{3}=140 v \\ U_{3}+U_{4}=160 v\end{array}
U
1
+
U
2
+
U
3
=
220
v
U
1
+
U
4
=
200
v
U
2
+
U
3
=
140
v
U
3
+
U
4
=
160
v
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f)
4
(
−
x
+
3
)
=
20
4(-x+3)=20
4
(
−
x
+
3
)
=
20
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Solve for
n
n
n
.
\newline
2
(
n
+
5
)
=
16
2(n + 5) = 16
2
(
n
+
5
)
=
16
\newline
n
=
n =
n
=
_____
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Solve for
t
t
t
.
\newline
18
=
3
(
t
+
3
)
18 = 3(t + 3)
18
=
3
(
t
+
3
)
\newline
t
=
t =
t
=
_
_
_
_
\_\_\_\_
____
Get tutor help
Solve for
q
q
q
.
\newline
3
(
q
−
14
)
+
3
=
18
3(q - 14) + 3 = 18
3
(
q
−
14
)
+
3
=
18
\newline
q
=
q =
q
=
_____
Get tutor help
Solve for
b
b
b
.
\newline
2
(
b
−
10
)
=
14
2(b - 10) = 14
2
(
b
−
10
)
=
14
\newline
b
=
b =
b
=
_____
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Solve for
y
y
y
.
\newline
16
=
4
(
y
+
1
)
16 = 4(y + 1)
16
=
4
(
y
+
1
)
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Solve for
s
s
s
.
\newline
16
=
2
(
s
−
9
)
16 = 2(s - 9)
16
=
2
(
s
−
9
)
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Solve for
y
y
y
.
\newline
4
(
y
−
12
)
=
16
4(y - 12) = 16
4
(
y
−
12
)
=
16
\newline
y
=
y =
y
=
_
_
_
_
_
\_\_\_\_\_
_____
Get tutor help
Solve for
f
f
f
.
\newline
2
(
f
−
12
)
=
10
2(f - 12) = 10
2
(
f
−
12
)
=
10
\newline
f
=
f =
f
=
_____
Get tutor help
Solve for
u
u
u
.
\newline
2
(
u
−
7
)
=
6
2(u - 7) = 6
2
(
u
−
7
)
=
6
\newline
u
=
u =
u
=
_____
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Solve for
y
y
y
.
\newline
3
(
y
+
4
)
=
15
3(y + 4) = 15
3
(
y
+
4
)
=
15
\newline
y
=
y =
y
=
_
_
_
_
\_\_\_\_
____
Get tutor help
Solve for
t
t
t
.
\newline
4
(
t
+
2
)
=
20
4(t + 2) = 20
4
(
t
+
2
)
=
20
\newline
t
=
t =
t
=
_____
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Solve for
k
k
k
.
\newline
2
(
k
+
7
)
=
20
2(k + 7) = 20
2
(
k
+
7
)
=
20
\newline
k
=
k =
k
=
_____
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Solve for
b
b
b
.
\newline
4
(
b
−
14
)
=
20
4(b - 14) = 20
4
(
b
−
14
)
=
20
\newline
b
=
b =
b
=
_____
Get tutor help
Solve for
t
t
t
.
\newline
2
(
t
−
12
)
=
6
2(t - 12) = 6
2
(
t
−
12
)
=
6
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Solve for
k
k
k
.
\newline
18
=
3
(
k
+
1
)
18 = 3(k + 1)
18
=
3
(
k
+
1
)
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Solve for
x
\mathrm{x}
x
.
\newline
7
3
+
x
−
1
21
=
x
+
8
\frac{7}{3}+\frac{x-1}{21}=x+8
3
7
+
21
x
−
1
=
x
+
8
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
3
x
−
5
8
−
3
x
−
9
40
=
2
\frac{3 x-5}{8}-\frac{3 x-9}{40}=2
8
3
x
−
5
−
40
3
x
−
9
=
2
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
2
x
+
1
4
−
2
x
+
1
36
=
−
2
\frac{2 x+1}{4}-\frac{2 x+1}{36}=-2
4
2
x
+
1
−
36
2
x
+
1
=
−
2
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
13
2
=
39
x
\frac{13}{2}=\frac{39}{x}
2
13
=
x
39
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
3
5
=
15
x
\frac{3}{5}=\frac{15}{x}
5
3
=
x
15
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
x
20
=
5
4
\frac{x}{20}=\frac{5}{4}
20
x
=
4
5
\newline
Answer:
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Solve for
x
\mathrm{x}
x
.
\newline
x
45
=
2
3
\frac{x}{45}=\frac{2}{3}
45
x
=
3
2
\newline
Answer:
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1
2
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