Find U_(1), U_(2), U_(3), U_(4). {:[U_(1)+U_(2)+U_(3)=220 v],[U_(1)+U_(4)=200 v],[U_(2)+U_(3)=140 v],[U_(3)+U_(4)=160 v]:}

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Write Equations: Write down the system of equations. We have the following system of equations: 1) U₁ + U₂ + U₃ = 220 V 2) U₁ + U₄ = 200 V 3) U₂ + U₃ = 140 V 4) U₃ + U₄ = 160 VSubtract to Find U₁: Subtract equation 3 from equation 1 to find U₁. By subtracting U₂ + U₃ from both sides of equation 1, we get: U₁ + U₂ + U₃ - (U₂ + U₃) = 220 V - 140 V U₁ = 80 VFind U₄: Substitute U₁ into equation 2 to find U₄. We know U₁ = 80 V, so we substitute it into equation 2: U₁ + U₄ = 200 V 80 V + U₄ = 200 V U₄ = 200 V - 80 V U₄ = 120 VFind U₂ and U₃: Substitute U₁ into equation 1 and then use equation 3 to find U₂ and U₃. We know U₁ = 80 V, so we substitute it into equation 1 and use equation 3: U₁ + U₂ + U₃ = 220 V 80 V + U₂ + U₃ = 220 V U₂ + U₃ = 220 V - 80 V U₂ + U₃ = 140 V Since U₂ + U₃ = 140 V is the same as equation 3, we do not have new information here. We need to use another equation to find U₂ and U₃.Find U₃: Substitute U₄ into equation 4 to find U₃. We know U₄ = 120 V, so we substitute it into equation 4: U₃ + U₄ = 160 V U₃ + 120 V = 160 V U₃ = 160 V - 120 V U₃ = 40 VFind U₂: Substitute U₃ into equation 3 to find U₂. We know U₃ = 40 V, so we substitute it into equation 3: U₂ + U₃ = 140 V U₂ + 40 V = 140 V U₂ = 140 V - 40 V U₂ = 100 V

Find $U_{1}, U_{2}, U_{3}, U_{4}$ . $\newline$ $\begin{array}{l}U_{1}+U_{2}+U_{3}=220 v \\ U_{1}+U_{4}=200 v \\ U_{2}+U_{3}=140 v \\ U_{3}+U_{4}=160 v\end{array}$

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