Solve for y. 3(y + 4) = 15 y = _____

Distribute 3 to terms: Distribute the 3 to both terms inside the parentheses. We need to apply the distributive property, which states that a(b + c) = ab + ac. In this case, we distribute 3 to both y and 4. 3(y + 4) = 3*y + 3*4 This simplifies to: 3y + 12 = 15Subtract 12 to isolate: Subtract 12 from both sides of the equation to isolate the term with y. To solve for y, we need to get y on one side of the equation by itself. We do this by subtracting 12 from both sides. 3y + 12 - 12 = 15 - 12 This simplifies to: 3y = 3Divide by 3 to solve: Divide both sides of the equation by 3 to solve for y. Now, we divide both sides by 3 to get y by itself. 3y / 3 = 3 / 3 This simplifies to: y = 1

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Math Problems

Grade 7

Solve two-step equations with parentheses

Full solution

Q. Solve for

y

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3(y + 4) = 15

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y =

\_\_\_\_

Distribute $3$ to terms: Distribute the $3$ to both terms inside the parentheses. $\newline$ We need to apply the distributive property, which states that $a(b + c) = ab + ac$ . In this case, we distribute $3$ to both $y$ and $4$ . $\newline$ $3(y + 4) = 3\cdot y + 3\cdot 4$ $\newline$ This simplifies to: $\newline$ $3y + 12 = 15$
Subtract $12$ to isolate: Subtract $12$ from both sides of the equation to isolate the term with $y$ . To solve for $y$ , we need to get $y$ on one side of the equation by itself. We do this by subtracting $12$ from both sides. $3y + 12 - 12 = 15 - 12$ This simplifies to: $3y = 3$
Divide by $3$ to solve: Divide both sides of the equation by $3$ to solve for $y$ . Now, we divide both sides by $3$ to get $y$ by itself. $\frac{3y}{3} = \frac{3}{3}$ This simplifies to: $y = 1$