D=1,874−0.55tThe distance, D, in meters, between an antarctic glacier and the coast t days after January 1, 2010 is approximated by the equation. How does the distance between the glacier and the coast change over time?Choose 1 answer:(A) The glacier moves 0.55 meters per day closer to the shore.(B) The glacier moves 1,874 meters per day closer to the shore.(C) The glacier moves 0.55 meters per day further from the shore.(D) The glacier moves 1,874 meters per day further from the shore. Get tutor help
h(t)=−4.9t2+18t+0.5 The equation models h, the height, in meters, of a soccer ball t seconds after the goalkeeper kicks it. Which of the following statements is the best interpretation of the ordered pair (3,10.4)?Choose 1 answer:(A) At 3 seconds after the kick, the distance between the soccer ball and the goalkeeper is 10.4 meters.(B) At 3 seconds after the kick, the soccer ball is traveling at a speed of 10.4 meters per second.(C) At 3 seconds after the kick, the height of the soccer ball is 10.4 meters.(D) At 10.4 seconds after the kick, the height of the soccer ball is 3 meters. Get tutor helpP=67,000+2,820mThe total payments, P, in dollars, made by a homeowner m months after starting payments on a home mortgage is given by the equation. What is the best interpretation of 67,000 as shown in the given equation?Choose 1 answer:(A) The first payment was 67,000 dollars.(B) The homeowner pays 67,000 dollars each month.(C) The homeowner paid 67,000 dollars at the end of the first month.(D) The total of all payments made by the homeowner is 67,000 dollars. Get tutor helpEitan posted a video on the internet which only received approximately 100 views per day for the first 365 days after it was posted. However, on the 366th day, Eitan's video began to receive a greater following: the total number of views grew at a rate of 25% per day. Compared to the number of views Eitan's video received in the first 365 days, how many more views did his video receive in the 7- day period after the first 365 days?Choose 1 answer:A) 36,500B) 101,000C) 138,000D) 3650 Get tutor helpA commercial airliner takes off from a runway with an elevation of 150 feet above sea level. The airliner's altitude above sea level increases at a linear rate of 3,000 feet each minute, m, after its takeoff time until it reaches its cruising altitude of 39,000 feet. Which of the following functions best models the altitude, a, of the airliner before it reaches its cruising altitude?Choose 1 answer:(A) a(m)=150+3,00039,000m(B) a(m)=39,150−3,000m(C) a(m)=150+3,000m(D) a(m)=3,000+150m Get tutor helpWalking on his own, the distance, D, in feet, that Roberto can cover in m minutes is given by the function D(m)=264m. When he walks on the moving sidewalk at the airport, the distance, A, in feet, that he can cover in m minutes is given by the functionA(m)=440m.Let B be the distance, in feet, that Roberto would travel on the moving sidewalk in m minutes if he were standing still.Write a formula for B(m) in terms of D(m) and A(m).B(m)=Write a formula for B(m) in terms of m.B(m)=□ Get tutor help
