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An investment lost approximately 5%5\% of the balance each month for the past year. The amount of the investment on January 1st1^{\text{st}} of last year was $10,000\$10,000. Which of the following functions, II, models the amount of the investment (in thousands of dollars) at the end of month, nn, where 1n121 \leq n \leq 12?\newlineChoose 11 answer:\newline(A) I(n)=10(1.05)nI(n)=10\cdot(1.05)^n thousand dollars\newline(B) I(n)=100.05nI(n)=10-0.05n thousand dollars\newline(C) I(n)=10(0.95)nI(n)=10\cdot(0.95)^n thousand dollars\newline(D) I(n)=10+0.95nI(n)=10+0.95n thousand dollars

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Q. An investment lost approximately 5%5\% of the balance each month for the past year. The amount of the investment on January 1st1^{\text{st}} of last year was $10,000\$10,000. Which of the following functions, II, models the amount of the investment (in thousands of dollars) at the end of month, nn, where 1n121 \leq n \leq 12?\newlineChoose 11 answer:\newline(A) I(n)=10(1.05)nI(n)=10\cdot(1.05)^n thousand dollars\newline(B) I(n)=100.05nI(n)=10-0.05n thousand dollars\newline(C) I(n)=10(0.95)nI(n)=10\cdot(0.95)^n thousand dollars\newline(D) I(n)=10+0.95nI(n)=10+0.95n thousand dollars
  1. Understand the problem: Understand the problem.\newlineThe investment loses 5%5\% of its balance each month. This means that each month, the investment retains 95%95\% (100%5%100\% - 5\%) of its value from the previous month. We need to find a function that models this situation over a period of 1212 months.
  2. Analyze the choices: Analyze the answer choices.\newlineWe need to determine which function correctly represents the investment losing 5%5\% of its value each month. The function should show the investment amount decreasing over time, not increasing, and it should be a function of nn, the number of months.
  3. Evaluate the answers: Evaluate the answer choices.\newline(A) I(n)=10×(1.05)nI(n)=10\times(1.05)^{n} thousand dollars - This function suggests the investment is increasing by 5%5\% each month, which is incorrect.\newline(B) I(n)=100.05nI(n)=10-0.05n thousand dollars - This function suggests a linear decrease, which is not how percentage losses work.\newline(C) I(n)=10×(0.95)nI(n)=10\times(0.95)^{n} thousand dollars - This function suggests the investment retains 95%95\% of its value each month, which matches the problem statement.\newline(D) I(n)=10+0.95nI(n)=10+0.95n thousand dollars - This function suggests the investment is increasing each month, which is incorrect.
  4. Choose the function: Choose the correct function.\newlineBased on the analysis in Step 33, the correct function is (C) I(n)=10×(0.95)nI(n)=10\times(0.95)^{n} thousand dollars, as it correctly models a 5%5\% loss each month.

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