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In an arithmetic sequence, the first term, 
a_(1), is equal to 9 , and the sixth term, 
a_(6), is equal to 39 . Which number represents the common difference of the arithmetic sequence?

d=5

d=6

d=7

d=8

In an arithmetic sequence, the first term, a1 a_{1} , is equal to 99 , and the sixth term, a6 a_{6} , is equal to 3939 . Which number represents the common difference of the arithmetic sequence?\newlined=5 d=5 \newlined=6 d=6 \newlined=7 d=7 \newlined=8 d=8

Full solution

Q. In an arithmetic sequence, the first term, a1 a_{1} , is equal to 99 , and the sixth term, a6 a_{6} , is equal to 3939 . Which number represents the common difference of the arithmetic sequence?\newlined=5 d=5 \newlined=6 d=6 \newlined=7 d=7 \newlined=8 d=8
  1. Identify Given Terms: Identify the given terms in the arithmetic sequence.\newlineWe are given the first term a1a_{1} and the sixth term a6a_{6} of the arithmetic sequence. The first term is 99, and the sixth term is 3939.
  2. Use Formula for nth Term: Use the formula for the nth term of an arithmetic sequence to find the common difference.\newlineThe nth term of an arithmetic sequence is given by the formula an=a1+(n1)da_n = a_1 + (n - 1)d, where a1a_1 is the first term, dd is the common difference, and nn is the term number.
  3. Plug Known Values: Plug the known values into the formula to create an equation.\newlineWe know that a6=39a_{6} = 39, a1=9a_{1} = 9, and n=6n = 6. We can substitute these values into the formula to find dd:\newline39=9+(61)d39 = 9 + (6 - 1)d
  4. Simplify and Solve: Simplify the equation and solve for dd.39=9+5d39 = 9 + 5d399=5d39 - 9 = 5d30=5d30 = 5dd=305d = \frac{30}{5}d=6d = 6

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