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Yasmin is the youngest of three siblings whose ages are consecutive integers. If the sum of their ages is 57, find Yasmin's age. Answer:

Yasmin is the youngest of three siblings whose ages are consecutive integers. If the sum of their ages is 5757, find Yasmin's age.\newlineAnswer:

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Full solution

Q. Yasmin is the youngest of three siblings whose ages are consecutive integers. If the sum of their ages is 5757, find Yasmin's age.\newlineAnswer:
  1. Define Yasmin's Age: Let yy be Yasmin's age, which is the first and smallest integer. Consecutive ages of the siblings: yy, y+1y+1, y+2y+2.
  2. Set Up Equation: Set up the equation that represents the sum of the siblings' ages as 5757. Equation: y+(y+1)+(y+2)=57y + (y+1) + (y+2) = 57.
  3. Simplify Equation: Simplify the left side of the equation y+(y+1)+(y+2)=57y + (y+1) + (y+2) = 57.y+(y+1)+(y+2)=57y + (y+1) + (y+2) = 57(y+y+y)+(1+2)=57(y + y + y) + (1+2) = 573y+3=573y + 3 = 57
  4. Isolate Variable Term: Isolate the variable term 3y3y in the equation 3y+3=573y + 3 = 57.
    3y+3=573y + 3 = 57
    3y+3−3=57−33y + 3 - 3 = 57 - 3
    3y=543y = 54
  5. Solve for y: Solve for y in the equation 3y=543y = 54.\newline3y=543y = 54\newline(3y)/3=54/3(3y)/3 = 54/3\newliney=18y = 18
  6. Final Result: Yasmin's age is the value of yy.
    Yasmin's age: y=18y = 18.

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