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How many solutions does the following equation have? -2z+10+7z=16 z+7 Choose 1 answer: (A) No solutions (B) Exactly one solution (c) Infinitely many solutions

How many solutions does the following equation have?\newline−2z+10+7z=16z+7-2z+10+7z=16z+7\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

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Q. How many solutions does the following equation have?\newline−2z+10+7z=16z+7-2z+10+7z=16z+7\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Combine like terms: Combine like terms on the left side of the equation. \newline−2z+10+7z-2z + 10 + 7z \newline=5z+10= 5z + 10
  2. Rewrite the equation: Rewrite the equation with the combined terms. 5z+10=16z+75z + 10 = 16z + 7
  3. Isolate zz: Move all terms containing zz to one side and constant terms to the other side to isolate zz.5z−16z=7−105z - 16z = 7 - 10
  4. Combine like terms: Combine like terms on both sides.\newline−11z=−3-11z = -3
  5. Solve for z: Solve for z by dividing both sides by -11＂).\(\newline\$z = \frac{-3}{-11}\)
  6. Simplify the fraction: Simplify the fraction. \(z = \frac{3}{11}\)

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