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How many solutions does the following equation have? 7(y-8)=7y+42 Choose 1 answer: (A) No solutions (B) Exactly one solution (C) Infinitely many solutions

How many solutions does the following equation have?\newline7(y−8)=7y+427(y-8)=7y+42\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions

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Q. How many solutions does the following equation have?\newline7(y−8)=7y+427(y-8)=7y+42\newlineChoose 11 answer:\newline(A) No solutions\newline(B) Exactly one solution\newline(C) Infinitely many solutions
  1. Distribute the 77: Distribute the 77 on the left side of the equation.\newline7(y−8)=7y+427(y-8) = 7y + 42\newline7⋅y−7⋅8=7y+427\cdot y - 7\cdot 8 = 7y + 42\newline7y−56=7y+427y - 56 = 7y + 42
  2. Subtract 7y7y: Subtract 7y7y from both sides to move all y terms to one side.\newline7y−7y−56=7y−7y+427y - 7y - 56 = 7y - 7y + 42\newline0−56=0+420 - 56 = 0 + 42\newline−56=42-56 = 42
  3. Analyze the statement: Analyze the resulting statement.\newline−56=42-56 = 42 is a false statement, which means there is no value of yy that can satisfy the equation.

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