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Let’s check out your problem:
Write the expression using exponents. Enter a number in every blank.
\newline
83
⋅
90
⋅
90
⋅
90
⋅
90
83 \cdot 90 \cdot 90 \cdot 90 \cdot 90
83
⋅
90
⋅
90
⋅
90
⋅
90
\newline
8
3
_
_
⋅
9
0
_
_
83^{\_\_}\cdot90^{\_\_}
8
3
__
⋅
9
0
__
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Math Problems
Grade 8
Writing from expanded to exponent form
Full solution
Q.
Write the expression using exponents. Enter a number in every blank.
\newline
83
⋅
90
⋅
90
⋅
90
⋅
90
83 \cdot 90 \cdot 90 \cdot 90 \cdot 90
83
⋅
90
⋅
90
⋅
90
⋅
90
\newline
8
3
_
_
⋅
9
0
_
_
83^{\_\_}\cdot90^{\_\_}
8
3
__
⋅
9
0
__
Group Like Terms:
Group the like terms in the expression
83
⋅
90
⋅
90
⋅
90
⋅
90
83 \cdot 90 \cdot 90 \cdot 90 \cdot 90
83
⋅
90
⋅
90
⋅
90
⋅
90
. Calculation:
83
83
83
is alone, while
90
90
90
appears four times.
Write Using Exponent:
Write
90
⋅
90
⋅
90
⋅
90
90 \cdot 90 \cdot 90 \cdot 90
90
⋅
90
⋅
90
⋅
90
using an exponent.
\newline
Calculation:
90
90
90
is multiplied by itself
4
4
4
times, so it becomes
9
0
4
90^4
9
0
4
.
Combine Using Exponents:
Combine the expressions using exponents.
\newline
Calculation: The expression becomes
8
3
1
⋅
9
0
4
83^1 \cdot 90^4
8
3
1
⋅
9
0
4
.
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\newline
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Question
Select the equivalent expression.
\newline
(
(
8
−
5
)
/
(
2
−
2
)
)
−
4
=
?
((8^{-5})/(2^{-2}))^{-4}=?
((
8
−
5
)
/
(
2
−
2
)
)
−
4
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
\newline
(
8
20
)
/
(
2
8
)
(8^{20})/(2^{8})
(
8
20
)
/
(
2
8
)
\newline
(B)
\newline
(
2
6
)
/
(
8
9
)
(2^{6})/(8^{9})
(
2
6
)
/
(
8
9
)
\newline
(C)
\newline
(
1
)
/
(
8
⋅
2
2
)
(1)/(8\cdot 2^{2})
(
1
)
/
(
8
⋅
2
2
)
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Posted 11 months ago
Question
Select the equivalent expression.
\newline
(
b
7
4
5
)
−
3
=
?
\left(\frac{b^{7}}{4^{5}}\right)^{-3}=\,?
(
4
5
b
7
)
−
3
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
b
21
4
15
\frac{b^{21}}{4^{15}}
4
15
b
21
\newline
(B)
4
15
b
21
\frac{4^{15}}{b^{21}}
b
21
4
15
\newline
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b
−
21
⋅
4
−
15
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−
21
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−
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Question
Select the equivalent expression.
\newline
(
3
3
⋅
6
6
)
−
3
=
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(
3
3
⋅
6
6
)
−
3
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
1
3
9
⋅
6
18
\frac{1}{3^{9}\cdot6^{18}}
3
9
⋅
6
18
1
\newline
(B)
6
18
3
9
\frac{6^{18}}{3^{9}}
3
9
6
18
\newline
(C)
3
9
6
18
\frac{3^{9}}{6^{18}}
6
18
3
9
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Posted 1 year ago
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