Q. Which value of x satisfies the equation 53(x−41)=−415 ?−7−676
Write Equation: Write down the equation that needs to be solved.(53)(x−41)=−415
Eliminate Fraction: To isolate x, we first need to get rid of the fraction on the left side by multiplying both sides of the equation by the reciprocal of 53, which is 35. Multiply both sides by 35: \left(\frac{\(5\)}{\(3\)}\right) \times \left(\frac{\(3\)}{\(5\)}\right)(x - \frac{\(1\)}{\(4\)}) = \left(\frac{\(5\)}{\(3\)}\right) \times \left(-\frac{\(15\)}{\(4\)}\right)
Simplify Equation: Simplify both sides of the equation. On the left side, the \(\frac{5}{3} and 53 cancel each other out, leaving us with x−41. On the right side, we multiply the numerators and denominators.x−41=(3×4)(5×−15)x−41=12−75
Isolate x: Simplify the fraction on the right side by dividing both the numerator and the denominator by their greatest common divisor, which is 3.x−41=12/3−75/3x−41=−425
Combine Fractions: Now, we need to isolate x by adding 41 to both sides of the equation.x=−425+41
Simplify x: Combine the fractions on the right side by finding a common denominator, which is already 4, and then adding the numerators.x=(−25+1)/4x=−24/4
Simplify x: Combine the fractions on the right side by finding a common denominator, which is already 4, and then adding the numerators.x=(−25+1)/4x=−24/4 Simplify the fraction on the right side by dividing the numerator by the denominator.x=−24/4x=−6
More problems from Add and subtract three or more integers