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Which sign makes the statement true? $\newline$ $\frac{6}{9} - \frac{3}{9}$ $\text{?}$ $\frac{1}{9} + \frac{3}{9}$ $\newline$ Choices: $\newline$ (A) > $\newline$ (B) < $\newline$ (C) $=$

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Inequalities with addition and subtraction of like and unlike fractions

Full solution

Q. Which sign makes the statement true?

\newline

\frac{6}{9} - \frac{3}{9}

\text{?}

\frac{1}{9} + \frac{3}{9}

\newline

Choices:

\newline

(A)

>

\newline

(B)

<

\newline

(C)

=

Simplify left side: Step $1$ : Simplify the left side of the equation. $\frac{6}{9} - \frac{3}{9} = \frac{3}{9}$
Simplify right side: Step $2$ : Simplify the right side of the equation. $\frac{1}{9} + \frac{3}{9} = \frac{4}{9}$
Compare results: Step $3$ : Compare the simplified results. $\frac{3}{9} ? \frac{4}{9}$
Determine inequality sign: Step $4$ : Determine the correct inequality sign. $\newline$ Since $\frac{3}{9}$ (which is $\frac{1}{3}$ ) is less than $\frac{4}{9}$ , the correct sign is <.

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