Lee's drive to work is $15\frac{1}{6}$ hours, whereas Duncan's is $11\frac{5}{6}$ hours. How much longer is Lee's drive than Duncan's? $\newline$ Write your answer as a fraction or as a whole or mixed number. $\newline$ $\_\_\_\_$ hours

Full solution

Q. Lee's drive to work is

15\frac{1}{6}

hours, whereas Duncan's is

11\frac{5}{6}

hours. How much longer is Lee's drive than Duncan's?

\newline

Write your answer as a fraction or as a whole or mixed number.

\newline

\_\_\_\_

hours

Convert Fractions: Convert Lee's and Duncan's driving times to improper fractions for easier calculation. Lee's time is $15 \frac{1}{6}$ hours, which converts to $(15\times6 + 1)/6 = \frac{91}{6}$ hours. Duncan's time is $11 \frac{5}{6}$ hours, which converts to $(11\times6 + 5)/6 = \frac{71}{6}$ hours.
Subtract Times: Subtract Duncan's driving time from Lee's to find the difference. Calculate $\frac{91}{6} - \frac{71}{6} = \frac{(91 - 71)}{6} = \frac{20}{6}$ hours.
Simplify Fraction: Simplify the fraction $\frac{20}{6}$ to its lowest terms. Divide both numerator and denominator by their greatest common divisor, which is $2$ . So, $\frac{20}{6} = \frac{(20/2)}{(6/2)} = \frac{10}{3}$ hours.