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Today Raymond is carrying his history textbook and his lunch in his backpack. If the history textbook weighs 1151\frac{1}{5} pounds and his lunch weighs 2252\frac{2}{5} pounds, how much weight is in Raymond's backpack?\newlineWrite your answer as a fraction or as a whole or mixed number.\newline___\_\_\_ pounds

Full solution

Q. Today Raymond is carrying his history textbook and his lunch in his backpack. If the history textbook weighs 1151\frac{1}{5} pounds and his lunch weighs 2252\frac{2}{5} pounds, how much weight is in Raymond's backpack?\newlineWrite your answer as a fraction or as a whole or mixed number.\newline___\_\_\_ pounds
  1. Add weights: Step 11: Add the weights of the history textbook and lunch. \newline1151 \frac{1}{5} pounds + 2252 \frac{2}{5} pounds.\newlineConvert mixed numbers to improper fractions for easier addition:\newline115=651 \frac{1}{5} = \frac{6}{5}, 225=1252 \frac{2}{5} = \frac{12}{5}.\newline65+125=185\frac{6}{5} + \frac{12}{5} = \frac{18}{5}.\newlineConvert back to a mixed number: 185=335\frac{18}{5} = 3 \frac{3}{5} pounds.