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Let’s check out your problem:
Which sign makes the statement true?
\newline
1
7
+
3
7
\frac{1}{7} + \frac{3}{7}
7
1
+
7
3
?
6
7
−
3
7
\frac{6}{7} - \frac{3}{7}
7
6
−
7
3
\newline
Choices:
\newline
(A) >
\newline
(B) <
\newline
(C) =
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Math Problems
Algebra 2
Simplify variable expressions using properties
Full solution
Q.
Which sign makes the statement true?
\newline
1
7
+
3
7
\frac{1}{7} + \frac{3}{7}
7
1
+
7
3
?
6
7
−
3
7
\frac{6}{7} - \frac{3}{7}
7
6
−
7
3
\newline
Choices:
\newline
(A) >
\newline
(B) <
\newline
(C) =
Simplify left side:
Simplify the left side of the expression:
1
7
+
3
7
\frac{1}{7} + \frac{3}{7}
7
1
+
7
3
.
\newline
Calculation:
1
7
+
3
7
=
4
7
\frac{1}{7} + \frac{3}{7} = \frac{4}{7}
7
1
+
7
3
=
7
4
.
Simplify right side:
Simplify the right side of the expression:
6
7
−
3
7
\frac{6}{7} - \frac{3}{7}
7
6
−
7
3
. Calculation:
6
7
−
3
7
=
3
7
\frac{6}{7} - \frac{3}{7} = \frac{3}{7}
7
6
−
7
3
=
7
3
.
Compare results:
Compare the simplified results:
4
7
?
3
7
\frac{4}{7} ? \frac{3}{7}
7
4
?
7
3
.
\newline
Calculation: Since
4
7
\frac{4}{7}
7
4
is greater than
3
7
\frac{3}{7}
7
3
, the correct sign is '>'.
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\newline
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Rewrite the expression in the form
k
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\newline
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\newline
3
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4
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Question
Let
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y=3^{x}
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\newline
Find
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4
x
2
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x
.
\newline
d
y
d
x
=
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\newline
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