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Which recursive sequence would produce the sequence 
5,-16,68,dots ?

a_(1)=5 and 
a_(n)=-3a_(n-1)-1

a_(1)=5 and 
a_(n)=-4a_(n-1)+4

a_(1)=5 and 
a_(n)=-a_(n-1)-3

a_(1)=5 and 
a_(n)=4a_(n-1)-4

Which recursive sequence would produce the sequence 5,16,68, 5,-16,68, \ldots ?\newlinea1=5 a_{1}=5 and an=3an11 a_{n}=-3 a_{n-1}-1 \newlinea1=5 a_{1}=5 and an=4an1+4 a_{n}=-4 a_{n-1}+4 \newlinea1=5 a_{1}=5 and an=an13 a_{n}=-a_{n-1}-3 \newlinea1=5 a_{1}=5 and an=4an14 a_{n}=4 a_{n-1}-4

Full solution

Q. Which recursive sequence would produce the sequence 5,16,68, 5,-16,68, \ldots ?\newlinea1=5 a_{1}=5 and an=3an11 a_{n}=-3 a_{n-1}-1 \newlinea1=5 a_{1}=5 and an=4an1+4 a_{n}=-4 a_{n-1}+4 \newlinea1=5 a_{1}=5 and an=an13 a_{n}=-a_{n-1}-3 \newlinea1=5 a_{1}=5 and an=4an14 a_{n}=4 a_{n-1}-4
  1. Test Formula 1-1: Let's test each given recursive sequence formula by applying it to the initial term a1=5a_{1}=5 and see which one produces the sequence 5,16,68,...5, -16, 68, ... .\newlineFirst, we test the recursive sequence formula an=3an11a_{n}=-3a_{n-1}-1 with a1=5a_{1}=5.\newlinea2=3×a11=3×51=151=16a_{2} = -3 \times a_{1} - 1 = -3 \times 5 - 1 = -15 - 1 = -16\newlinea3=3×a21=3×(16)1=481=47a_{3} = -3 \times a_{2} - 1 = -3 \times (-16) - 1 = 48 - 1 = 47\newlineThe third term does not match the given sequence (6868), so this formula is incorrect.
  2. Test Formula 2-2: Next, we test the recursive sequence formula an=4an1+4a_{n}=-4a_{n-1}+4 with a1=5a_{1}=5.\newlinea2=4×a1+4=4×5+4=20+4=16a_{2} = -4 \times a_{1} + 4 = -4 \times 5 + 4 = -20 + 4 = -16\newlinea3=4×a2+4=4×(16)+4=64+4=68a_{3} = -4 \times a_{2} + 4 = -4 \times (-16) + 4 = 64 + 4 = 68\newlineThe third term matches the given sequence (6868), so this formula seems to be correct. Let's continue to verify with the fourth term.\newlinea4=4×a3+4=4×68+4=272+4=268a_{4} = -4 \times a_{3} + 4 = -4 \times 68 + 4 = -272 + 4 = -268\newlineThe fourth term is 268-268, which continues the pattern of the sequence. Therefore, this formula is correct.
  3. Test Formula 3-3: We do not need to test the remaining options because we have already found the correct formula. However, for completeness, let's quickly check the third option.\newlineTesting the recursive sequence formula an=an13a_{n}=-a_{n-1}-3 with a1=5a_{1}=5.\newlinea2=a13=53=8a_{2} = -a_{1} - 3 = -5 - 3 = -8\newlineThe second term does not match the given sequence (16)(-16), so this formula is incorrect.
  4. Test Formula 4-4: Finally, we test the recursive sequence formula an=4an14a_{n}=4a_{n-1}-4 with a1=5a_{1}=5.\newlinea2=4×a14=4×54=204=16a_{2} = 4 \times a_{1} - 4 = 4 \times 5 - 4 = 20 - 4 = 16\newlineThe second term does not match the given sequence (16-16), so this formula is incorrect.

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