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Find the derivative of g(x) g(x). \newline g(x)=ln(2x) g(x) = \ln(2x) \newline g(x)= g^{\prime}(x) = ______

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Q. Find the derivative of g(x) g(x). \newline g(x)=ln(2x) g(x) = \ln(2x) \newline g(x)= g^{\prime}(x) = ______
  1. Identify function to differentiate: Identify the function to differentiate. The function is g(x)=ln(2x)g(x) = \ln(2x).
  2. Apply chain rule for differentiation: Apply the chain rule for differentiation. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. The outer function is ln(u)\ln(u) with u=2xu = 2x, and the derivative of ln(u)\ln(u) with respect to uu is 1u\frac{1}{u}. The inner function is 2x2x, and its derivative with respect to xx is 22.
  3. Calculate derivative of inner function: Calculate the derivative of the inner function. The derivative of 2x2x with respect to xx is 22.
  4. Apply chain rule using derivatives: Apply the chain rule using the derivatives from steps 22 and 33. The derivative of g(x)g(x) is (12x)2\left(\frac{1}{2x}\right) \cdot 2.
  5. Simplify the expression: Simplify the expression. Multiplying 12x\frac{1}{2x} by 22 gives us 1x\frac{1}{x}.
  6. Write final answer: Write the final answer. The derivative of g(x)=ln(2x)g(x) = \ln(2x) is g(x)=1xg'(x) = \frac{1}{x}.

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