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Which ordered pair is a solution of the equation? \newline4x+7=2y3-4x+7=2y-3 \newlineChoose 11 answer:\newline(A) Only (2,1)(2,1)\newline(B) Only (5,5)(5,-5)\newline(C) Both (2,1)(2,1) and (5,5)(5,-5)\newline(D) Neither

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Q. Which ordered pair is a solution of the equation? \newline4x+7=2y3-4x+7=2y-3 \newlineChoose 11 answer:\newline(A) Only (2,1)(2,1)\newline(B) Only (5,5)(5,-5)\newline(C) Both (2,1)(2,1) and (5,5)(5,-5)\newline(D) Neither
  1. Solve for y: To find an ordered pair that is a solution to the equation, we need to express yy in terms of xx or xx in terms of yy. Let's solve for yy first.4x+7=2y3-4x + 7 = 2y - 3 Add 33 to both sides to isolate the terms with yy on one side.4x+7+3=2y3+3-4x + 7 + 3 = 2y - 3 + 34x+10=2y-4x + 10 = 2y
  2. Divide by 22: Now, divide both sides by 22 to solve for y.\newline(4x+10)/2=2y/2(-4x + 10) / 2 = 2y / 2\newline2x+5=y-2x + 5 = y\newlineNow we have yy expressed in terms of xx.
  3. Choose x=0x = 0: To find an ordered pair, we can choose any value for xx and then find the corresponding value for yy using the equation y=2x+5y = -2x + 5. Let's choose x=0x = 0 for simplicity.\newliney=2(0)+5y = -2(0) + 5\newliney=5y = 5\newlineSo, when x=0x = 0, y=5y = 5.
  4. Find Ordered Pair: The ordered pair that is a solution to the equation is (0,5)(0, 5).

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