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which ordered pair is a solution of the equation? \newline3x+5y=2x+3y-3x+5y=2x+3y \newlineChoose 11 answer:\newline(A) Only (2,4)(2,4)\newline(B) Only (3,3)(3,3)\newline(C) Both (2,4)(2,4) and (3,3)(3,3)\newline(D) Neither

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Q. which ordered pair is a solution of the equation? \newline3x+5y=2x+3y-3x+5y=2x+3y \newlineChoose 11 answer:\newline(A) Only (2,4)(2,4)\newline(B) Only (3,3)(3,3)\newline(C) Both (2,4)(2,4) and (3,3)(3,3)\newline(D) Neither
  1. Combine like terms: Simplify the equation by combining like terms.\newlineWe want to get all the xx terms on one side and all the yy terms on the other side.\newline3x+5y=2x+3y-3x + 5y = 2x + 3y\newlineAdd 3x3x to both sides to move the xx terms to one side:\newline3x+3x+5y=2x+3x+3y-3x + 3x + 5y = 2x + 3x + 3y\newlineThis simplifies to:\newline5y=5x+3y5y = 5x + 3y
  2. Move x terms: Subtract 3y3y from both sides to isolate the y terms.\newline5y3y=5x+3y3y5y - 3y = 5x + 3y - 3y\newlineThis simplifies to:\newline2y=5x2y = 5x
  3. Isolate y terms: Divide both sides by 22 to solve for yy in terms of xx.2y2=5x2\frac{2y}{2} = \frac{5x}{2}This simplifies to:y=(52)xy = \left(\frac{5}{2}\right)x
  4. Solve for yy: Test the ordered pairs to see which one(s) satisfy the equation y=52xy = \frac{5}{2}x. For (A) (2,4)(2,4), substitute x=2x = 2 and y=4y = 4 into the equation: 4=52(2)4 = \frac{5}{2}(2) 4=54 = 5 This is not true, so (2,4)(2,4) is not a solution.
  5. Test 2,42,4: Test the ordered pair BB 3,33,3.\newlineSubstitute x=3x = 3 and y=3y = 3 into the equation:\newline3=(52)(3)3 = \left(\frac{5}{2}\right)(3)\newline3=1523 = \frac{15}{2}\newlineThis is not true, so 3,33,3 is not a solution.
  6. Test 3,33,3: Since neither (A) 2,42,4 nor (B) 3,33,3 satisfy the equation y=52xy = \frac{5}{2}x, the correct answer is (D) Neither.

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