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Let’s check out your problem:
Which of the following expressions are equivalent to
\newline
J
−
k
\frac{J}{-k}
−
k
J
?
\newline
Choose all answers that apply:
\newline
A
\newline
−
j
−
k
-\frac{j}{-k}
−
−
k
j
\newline
(B)
\newline
−
−
j
k
-\frac{-j}{k}
−
k
−
j
\newline
(c) None of the above
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Math Problems
Algebra 1
Multiplication with rational exponents
Full solution
Q.
Which of the following expressions are equivalent to
\newline
J
−
k
\frac{J}{-k}
−
k
J
?
\newline
Choose all answers that apply:
\newline
A
\newline
−
j
−
k
-\frac{j}{-k}
−
−
k
j
\newline
(B)
\newline
−
−
j
k
-\frac{-j}{k}
−
k
−
j
\newline
(c) None of the above
Check option A:
Check option A:
−
j
−
k
-\frac{j}{-k}
−
−
k
j
\newline
Simplify:
−
j
−
k
=
j
k
-\frac{j}{-k} = \frac{j}{k}
−
−
k
j
=
k
j
Check option B:
Check option B:
−
(
−
j
)
k
\frac{-(-j)}{k}
k
−
(
−
j
)
\newline
Simplify:
−
(
−
j
)
k
\frac{-(-j)}{k}
k
−
(
−
j
)
=
j
k
\frac{j}{k}
k
j
Check option C:
Check option C: None of the above
\newline
Since both A and B are equivalent to
(
J
)
/
(
−
k
)
(J)/(-k)
(
J
)
/
(
−
k
)
, option C is incorrect.
More problems from Multiplication with rational exponents
Question
Let
h
(
x
)
=
log
2
(
x
)
h(x)=\log _{2}(x)
h
(
x
)
=
lo
g
2
(
x
)
.
\newline
Can we use the mean value theorem to say the equation
h
′
(
x
)
=
1
h^{\prime}(x)=1
h
′
(
x
)
=
1
has a solution where
1
<
x
<
2
1<x<2
1
<
x
<
2
?
\newline
Choose
1
1
1
answer:
\newline
(A) No, since the function is not differentiable on that interval.
\newline
(B) No, since the average rate of change of
h
h
h
over the interval
1
≤
x
≤
2
1 \leq x \leq 2
1
≤
x
≤
2
isn't equal to
1
1
1
.
\newline
(C) Yes, both conditions for using the mean value theorem have been met.
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What is the sign of
39
11
13
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(
−
41
1
13
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?
39 \frac{11}{13}+\left(-41 \frac{1}{13}\right) \text { ? }
39
13
11
+
(
−
41
13
1
)
?
\newline
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1
1
1
answer:
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(A) Positive
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(B) Negative
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(C) Neither positive nor negative-the sum is zero.
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What is the sign of
−
1042
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-1042+1042 ?
−
1042
+
1042
?
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1
1
1
answer:
\newline
(A) Positive
\newline
(B) Negative
\newline
(C) Neither positive nor negative-the sum is zero.
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What is the sign of
−
18
9
17
+
(
−
18
9
17
)
-18 \frac{9}{17}+\left(-18 \frac{9}{17}\right)
−
18
17
9
+
(
−
18
17
9
)
?
\newline
Choose
1
1
1
answer:
\newline
(A) Positive
\newline
(B) Negative
\newline
(C) Neither positive nor negative-the sum is zero.
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What is the sign of
23
45
+
(
−
23
45
)
?
\frac{23}{45}+\left(-\frac{23}{45}\right) ?
45
23
+
(
−
45
23
)
?
\newline
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1
1
1
answer:
\newline
(A) Positive
\newline
(B) Negative
\newline
(C) Neither positive nor negative-the sum is zero.
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What is the sign of
45
+
(
−
38
)
45+(-38)
45
+
(
−
38
)
?
\newline
Choose
1
1
1
answer:
\newline
(A) Positive
\newline
(B) Negative
\newline
(C) Neither positive nor negative-the sum is zero.
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What is the sign of
−
49.8
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61.2
-49.8+61.2
−
49.8
+
61.2
?
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1
1
1
answer:
\newline
(A) Positive
\newline
(B) Negative
\newline
(C) Neither positive nor negative-the sum is zero.
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What is the sign of
−
1.69
+
(
−
1.69
)
?
-1.69+(-1.69) ?
−
1.69
+
(
−
1.69
)?
\newline
Choose
1
1
1
answer:
\newline
(A) Positive
\newline
(B) Negative
\newline
(C) Neither positive nor negative-the sum is zero.
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Question
What is the sign of
37
+
(
−
37
)
37+(-37)
37
+
(
−
37
)
?
\newline
Choose
1
1
1
answer:
\newline
(A) Positive
\newline
(B) Negative
\newline
(C) Neither positive nor negative-the sum is zero.
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Question
g
(
x
)
=
2
x
−
9
g
′
(
x
)
=
?
\begin{array}{l} g(x)=\sqrt{2 x-9} \\ g^{\prime}(x)=? \end{array}
g
(
x
)
=
2
x
−
9
g
′
(
x
)
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
2
x
−
9
2
\frac{\sqrt{2 x-9}}{2}
2
2
x
−
9
\newline
(B)
1
2
x
−
9
\frac{1}{\sqrt{2 x-9}}
2
x
−
9
1
\newline
(C)
1
2
2
x
−
9
\frac{1}{2 \sqrt{2 x-9}}
2
2
x
−
9
1
\newline
(D)
1
x
\frac{1}{\sqrt{x}}
x
1
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Posted 9 months ago
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