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Let’s check out your problem:
Which is equal to
8
−
3
8^{-3}
8
−
3
?
\newline
Choices:
\newline
(A)
−
8
3
-8^3
−
8
3
\newline
(B)
1
8
3
\frac{1}{8^3}
8
3
1
\newline
(C)
−
1
(
−
8
)
−
3
-\frac{1}{(-8)^{-3}}
−
(
−
8
)
−
3
1
\newline
(D)
−
1
8
−
3
-\frac{1}{8^{-3}}
−
8
−
3
1
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Math Problems
Grade 8
Understanding negative exponents
Full solution
Q.
Which is equal to
8
−
3
8^{-3}
8
−
3
?
\newline
Choices:
\newline
(A)
−
8
3
-8^3
−
8
3
\newline
(B)
1
8
3
\frac{1}{8^3}
8
3
1
\newline
(C)
−
1
(
−
8
)
−
3
-\frac{1}{(-8)^{-3}}
−
(
−
8
)
−
3
1
\newline
(D)
−
1
8
−
3
-\frac{1}{8^{-3}}
−
8
−
3
1
Identify Base and Exponent:
Identify the base and the exponent in
8
−
3
8^{-3}
8
−
3
.
\newline
Base:
8
8
8
, Exponent:
−
3
-3
−
3
.
Rewrite Using Property:
Rewrite the expression
8
−
3
8^{-3}
8
−
3
using the property of
negative exponents
, which states that
a
−
n
=
1
a
n
a^{-n} = \frac{1}{a^n}
a
−
n
=
a
n
1
.
\newline
So,
8
−
3
=
1
8
3
8^{-3} = \frac{1}{8^3}
8
−
3
=
8
3
1
.
Match with Choices:
Match the rewritten expression with the given choices.
\newline
1
8
3
\frac{1}{8^3}
8
3
1
corresponds to choice (B).
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\newline
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\newline
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\newline
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Question
Select the equivalent expression.
\newline
(
(
8
−
5
)
/
(
2
−
2
)
)
−
4
=
?
((8^{-5})/(2^{-2}))^{-4}=?
((
8
−
5
)
/
(
2
−
2
)
)
−
4
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
\newline
(
8
20
)
/
(
2
8
)
(8^{20})/(2^{8})
(
8
20
)
/
(
2
8
)
\newline
(B)
\newline
(
2
6
)
/
(
8
9
)
(2^{6})/(8^{9})
(
2
6
)
/
(
8
9
)
\newline
(C)
\newline
(
1
)
/
(
8
⋅
2
2
)
(1)/(8\cdot 2^{2})
(
1
)
/
(
8
⋅
2
2
)
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Posted 11 months ago
Question
Select the equivalent expression.
\newline
(
b
7
4
5
)
−
3
=
?
\left(\frac{b^{7}}{4^{5}}\right)^{-3}=\,?
(
4
5
b
7
)
−
3
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
b
21
4
15
\frac{b^{21}}{4^{15}}
4
15
b
21
\newline
(B)
4
15
b
21
\frac{4^{15}}{b^{21}}
b
21
4
15
\newline
(C)
b
−
21
⋅
4
−
15
b^{-21}\cdot 4^{-15}
b
−
21
⋅
4
−
15
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Question
Select the equivalent expression.
\newline
(
3
3
⋅
6
6
)
−
3
=
(3^{3}\cdot6^{6})^{-3}=
(
3
3
⋅
6
6
)
−
3
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
1
3
9
⋅
6
18
\frac{1}{3^{9}\cdot6^{18}}
3
9
⋅
6
18
1
\newline
(B)
6
18
3
9
\frac{6^{18}}{3^{9}}
3
9
6
18
\newline
(C)
3
9
6
18
\frac{3^{9}}{6^{18}}
6
18
3
9
Get tutor help
Posted 1 year ago
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